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Slav-nsk [51]
4 years ago
8

A friend of yours who has not taken astronomy sees a meteor shower (she calls it a bunch of shooting stars). The next day she co

nfides in you that she was concerned that the stars in the Big Dipper (her favorite star pattern) might be the next ones to go. How would you put her mind at ease?
Physics
1 answer:
Oxana [17]4 years ago
3 0
Tell her meteors and stars aren't related a stars life time is extremely long and meteors are just rocks floating through space when they fly be the earth they can appear like falling stars but they aren't her fave constellation wont be going away any time soon
You might be interested in
What wave phenomena best describes the reason for the dark and light bands that
pickupchik [31]

Answer:

Interference

Explanation:

Interference is the phenomenon in which two waves superimpose to form a wave with smaller, larger or same amplitude.

There are two types of interference namely, constructive interference and destructive interference.

Constructive interference occurs when the waves are in phase and destructive interference occurs when the waves are out of phase.

In a double slit experiment, the two slits acts as sources of light and thus the waves combine to produce interference patterns. When the waves are in phase, that is the angle between them is 0°, they form a constructive interference pattern which gives rise to a light band. When the waves are out of phase, that is the angle between them is 180°, they form a destructive interference pattern which gives rise to a dark band.

Note also that diffraction patterns are also observed for wide slits but can be neglected for smaller slits.

4 0
3 years ago
Two people, one with mass m1 and the other with mass m2, stand on a stationary sled with mass M on a frozen lake. Assume that th
lozanna [386]

Answer:

Part a)

Velocity of sled

v = \frac{m_1 s}{m_1 + m_2 + M}

velocity of first man who jump off

v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}

Part b)

Velocity of sled

v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s

Also the speed of second person is given as

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}

Part c)

change in kinetic energy of sled + two people is given as

KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2

Explanation:

As we know that here we we consider both people + sled as a system then there is no external force on it

So here we can use momentum conservation

since both people + sled is at rest initially so initial total momentum is zero

now when first people will jump with relative velocity "s" then let say the sled + other people will move off with speed v

so by momentum conservation we have

0 = m_1(v - s) + (m_2 + M)v

v = \frac{m_1 s}{m_1 + m_2 + M}

so velocity of the sled + other person is

v = \frac{m_1 s}{m_1 + m_2 + M}

velocity of first man who jump off

v_1 = \frac{m_1 s}{m_1 + m_2 + M} - s

v_1 = -\frac{(m_2 + M) s}{m_1 + m_2 + M}

Part b)

now when other man also jump off with same relative velocity

so let say the sled is now moving with speed vf

so by momentum conservation we have

(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) = m_2(v_f - s) + Mv_f

(m_2 + M)(\frac{m_1 s}{m_1 + m_2 + M}) + m_2s = (m_2 + M)v_f

Now we have

v_f = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s

Also the speed of second person is given as

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) + (\frac{m_2}{m_2 + M})s - s

v_2 = (\frac{m_1 s}{m_1 + m_2 + M}) - \frac{Ms}{m_2 + M}

Part c)

change in kinetic energy of sled + two people is given as

KE = \frac{1}{2}Mv_f^2 + \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2

here we know all values of speed as we found it in part a) and part b)

4 0
3 years ago
A single output device has failed while the remainder of the PLC system is functioning normally The indicator light on the outpu
Dmitry_Shevchenko [17]

Answer:

check the point where the output device's field wiring is connected to the output rack. ( C )

Explanation:

Given that an indicator light on the output module is indicating that a signal has been sent to the output point where the failed single output device is connected , the best line of action to properly indicate the output device that has filed in the PLC system, is to check the point where the output device's field wiring is connected to the output rack in the PLC system.

A PLC system is a computer control system ( especially Industrial ) that helps in the monitoring the states of input and output devices in an industry.

8 0
3 years ago
4. An object is thrown vertically upward with a speed of 25 m/s. How much time passes before it
vlada-n [284]

Answer:

<em>Option b is correct: 4.1 s</em>

Explanation:

<u>Vertical Launch</u>

An object launched thrown vertically upward where air resistance is negligible, reaches its maximum height in a time t, given by the equation:

\displaystyle t=\frac{v_o}{g}\qquad\qquad[1]

Where vo is the initial speed and g is the acceleration of gravity g=9.8 m/s^2.

Once the object reaches that point, it starts a free-fall motion, whose speed is (downward) given by:

v_f=g.t\qquad\qquad[2]

The object considered in the question is thrown with vo=25 m/s. The time taken to reach the maximum height is given by [1]:

\displaystyle t=\frac{25}{9.8}=2.551\ sec

The object starts its falling motion and at some time, it has a speed of vf=15 m/s. Let's find the time by solving [2] for t:

\displaystyle t=\frac{15}{9.8}=1.531\ sec

The total time taken by the object to go up and down is

t_t=2.551\ s+1.531\ s=4.081\ s

a. This option is incorrect because it's far away from the answer.

d. This option is incorrect because it's far away from the answer.

b. This option is correct because it's a good approximation to the calculated answer.

e. This option is incorrect because it's far away from the answer.

c. This option is incorrect because it's far away from the answer.

5 0
3 years ago
You weigh 680 N.
Alchen [17]

Answer:

132.22 N

Explanation:

Weight at the surface of a planet is:

W = GMm / r²

where G is the gravitational constant,

M is the mass of the planet,

m is the mass of the object,

and r is the radius of the planet.

On Earth:

680 N = GMm / r²

If Earth's mass and radius were changed:

W = G (7M) m / (6r)²

W = 7/36 GMm / r²

W = 7/36 (680 N)

W = 132.22 N

4 0
3 years ago
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