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bazaltina [42]
3 years ago
13

Now suppose you carry out a second Thomson experiment with a different beam that contains two types of particles. In particular,

both types have the same mass m as an electron, but one has charge e and the other has charge 2e. The beam is filtered, such that both types of particle have the same speed. As in the previous experiment, initially only the electric field is imposed and the deflection of the beam is observed as a spot on the screen; then, in the second phase of the experiment, one attempts to tune the magnetic field to exactly cancel the effect of the electric field. What would you observe on the screen during this experimentTwo off-centered spots in both the first and the second phases of the experiment
Two off-centered spots in the first phase of the experiment; one centered spot in the second phase of the experiment
Two off-centered spots in the first phase of the experiment; one centered and one off-centered spot in the second phase of the experiment
One off-centered spot in the first phase of the experiment; one centered and one off-centered spot in the second phase of the experiment
One off-centered spot in the first phase of the experiment; two off-centered spots in the second phase of the experiment
One off-centered spot in both the first and the second phases of the experiment
Physics
1 answer:
Tems11 [23]3 years ago
8 0

Answer:

Two off-centered spots in the first phase of the experiment; one centered spot in the second phase of the experiment.

Explanation:

If two particles are selected in which both have the same electron mass and the same velocity, but one of the particles has a charge and the other particle has a charge of 2e. During the first stage of the experiment, the two particles have an electric force equal to F = Eq in the entire vertical direction. The acceleration of particle is equal to a = (Eq)/m.

In the second part of the experiment, the magnetic field cancels the electric field. In this way, the electric force and the magnetic force cancel each other out. Therefore, the net force acting on each particle is equal to zero.

Because these two forces cancel each other out, the particles fail to create two off-center points on the screen in the second part of the experiment. Also, if the loads are different, the deviation is also different. In this way, an off-center point cannot be achieved in the first part of the experiment. There will be two off-center points.

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The average speed would be  0.65 m/s, therefore the correct option is (A).

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