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bazaltina [42]
3 years ago
13

Now suppose you carry out a second Thomson experiment with a different beam that contains two types of particles. In particular,

both types have the same mass m as an electron, but one has charge e and the other has charge 2e. The beam is filtered, such that both types of particle have the same speed. As in the previous experiment, initially only the electric field is imposed and the deflection of the beam is observed as a spot on the screen; then, in the second phase of the experiment, one attempts to tune the magnetic field to exactly cancel the effect of the electric field. What would you observe on the screen during this experimentTwo off-centered spots in both the first and the second phases of the experiment
Two off-centered spots in the first phase of the experiment; one centered spot in the second phase of the experiment
Two off-centered spots in the first phase of the experiment; one centered and one off-centered spot in the second phase of the experiment
One off-centered spot in the first phase of the experiment; one centered and one off-centered spot in the second phase of the experiment
One off-centered spot in the first phase of the experiment; two off-centered spots in the second phase of the experiment
One off-centered spot in both the first and the second phases of the experiment
Physics
1 answer:
Tems11 [23]3 years ago
8 0

Answer:

Two off-centered spots in the first phase of the experiment; one centered spot in the second phase of the experiment.

Explanation:

If two particles are selected in which both have the same electron mass and the same velocity, but one of the particles has a charge and the other particle has a charge of 2e. During the first stage of the experiment, the two particles have an electric force equal to F = Eq in the entire vertical direction. The acceleration of particle is equal to a = (Eq)/m.

In the second part of the experiment, the magnetic field cancels the electric field. In this way, the electric force and the magnetic force cancel each other out. Therefore, the net force acting on each particle is equal to zero.

Because these two forces cancel each other out, the particles fail to create two off-center points on the screen in the second part of the experiment. Also, if the loads are different, the deviation is also different. In this way, an off-center point cannot be achieved in the first part of the experiment. There will be two off-center points.

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Kim was adopted as a baby and raised by loving parents in an enriched environment. Studies have shown that ________
erik [133]

Answer:

Kim was adopted as a baby and raised by loving parents in an enriched environment. Studies have shown that the correlation between IQ

( intelligence quotient) scores of adopted children and those of their biologically unrelated family members reduce to zero as they grow into adulthood.

Explanation:

Kim was adopted as a baby and raised by loving parents in an enriched environment. Studies have shown that the correlation between IQ

( intelligence quotient) scores of adopted children and those of their biologically unrelated family members reduce to zero as they grow into adulthood.

Also, a loving environment is equally important for a child's upbringing.

8 0
3 years ago
Help please i give brainlyest
Natasha2012 [34]

D is the correct answer!

3 0
3 years ago
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If you want to calculate the acceleration of a car, you should _____ the change in velocity of the car by the time interval.
Neporo4naja [7]

Answer:

Your awnser is B. Increase

Explanation:

5 0
3 years ago
Read 2 more answers
HURRY
motikmotik

Answer:

12

N

in the direction opposite to electric field.

Explanation:

Force on a charged particle

q

due to electric field

E

is given by

→

F

=

q

→

E

|

F

|

=

−

0.06

C

×

200

N

C

=

−

12 N

Here negative indicates that force is in the direction opposite to electric field.

6 0
2 years ago
A negative charge of -0.550 m exerts an upward <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="5868766e
almond37 [142]

Answer:

a. +10.9μC

b. 0.600N and downward

Explanation:

To determine the magnitude of the charge, we use the force rule that exist between two charges which us expressed as

F=(kq₁q₂)/r²

since q₁=-0.55μC and the force it applied on the charge above it is upward,we can conclude that the second charge is +ve, hence we calculate its magnitude as

q₂=Fr²/kq₁

q₂=(0.6N*0.3²)/(9*10⁹*0.55*10⁻⁶)

q₂=0.054/4950

q₂=1.09*10⁻⁵c

q₂=10.9μC.

Hence the second charge is +10.9μC

b. From the rule of charges which state that like charges repel and unlike charges attract, we can conclude that the two above charges will attract since they are unlike charges. Hence the direction of the force will be downward into the second charge and the magnitude of the force will remain the same as 0.600N

8 0
4 years ago
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