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Zielflug [23.3K]
3 years ago
10

Experiments were carried out in which a beam of cathode rays was first bent by a magnetic field and then bent back by an electro

static field until the beam hit the screen exactly where it had been hitting before the fields were applied. This experiment permitted the direct measurement of a. the ratio of mass to charge of an electron. b. the charge on the nucleus of an atom. c. the charge on the electron. d. the mass of the atom. e. the mass of the electron.
Chemistry
1 answer:
Sergio039 [100]3 years ago
6 0

a. the ratio of mass to charge of an electron

Explanation:

The experiment permitted the direct measurement of the ratio of mass to charge of an electron.

  • The charge to mass ratio of an electron was determine by accelerating a beam of cathode rays in magnetic and electric fields.
  • No matter the gas used in the tube or the nature of the material of the electrodes, the rays were found to have constant charge to mass ratio of 1.76 x 10¹¹coulombkg⁻¹.

learn more:

Subatomic particles brainly.com/question/2757829

#learnwithBrainly

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Answer:

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2 years ago
Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu
pochemuha

Answer : The volume of CO_2 will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2

First we have to calculate the  mass of HCO_3^- in tablet.

\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g

Now we have to calculate the moles of HCO_3^-.

Molar mass of HCO_3^- = 1 + 12 + 3(16) = 61 g/mole

\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles

Now we have to calculate the moles of CO_2.

From the balanced chemical reaction, we conclude that

As, 1 mole of HCO_3^- react to give 1 mole of CO_2

So, 0.0202 mole of HCO_3^- react to give 0.0202 mole of CO_2

The moles of CO_2 = 0.0202 mole

Now we have to calculate the volume of CO_2 by using ideal gas equation.

PV=nRT

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = 37^oC=273+37=310K

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)

V=0.51411L=514.11ml

Therefore, the volume of CO_2 will be, 514.11 ml

6 0
2 years ago
What is the molarity of a solution that has 2.50 moles of NaOH dissolved in 0.500 L of solution?
const2013 [10]

Answer: 5 is the molarity

Explanation:

The molarity formula is moles over liters and that in your case is 2.50 moles divided by .500 L which results in 5 which is your answear hope this helped god bless

5 0
3 years ago
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guajiro [1.7K]

Answer:

D

Explanation:

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7 0
2 years ago
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