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Zielflug [23.3K]
3 years ago
10

Experiments were carried out in which a beam of cathode rays was first bent by a magnetic field and then bent back by an electro

static field until the beam hit the screen exactly where it had been hitting before the fields were applied. This experiment permitted the direct measurement of a. the ratio of mass to charge of an electron. b. the charge on the nucleus of an atom. c. the charge on the electron. d. the mass of the atom. e. the mass of the electron.
Chemistry
1 answer:
Sergio039 [100]3 years ago
6 0

a. the ratio of mass to charge of an electron

Explanation:

The experiment permitted the direct measurement of the ratio of mass to charge of an electron.

  • The charge to mass ratio of an electron was determine by accelerating a beam of cathode rays in magnetic and electric fields.
  • No matter the gas used in the tube or the nature of the material of the electrodes, the rays were found to have constant charge to mass ratio of 1.76 x 10¹¹coulombkg⁻¹.

learn more:

Subatomic particles brainly.com/question/2757829

#learnwithBrainly

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The solubility of KClO3(s) in water increases as the
algol [13]
<span>Answer: option (1) solubility of the solution increases.
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<span>Justification:
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<span>The solubility of substances in a given solvent is temperature dependent.
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<span>The most common behavior of the solubility of salts in water is that the solubiilty increases as the temperature increase.
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<span>To predict with certainty the solubility at different temperatures you need the product solubility constants (Kps), which is a constant of equlibrium of the dissolution of a ionic compound slightly soluble in water, or a chart (usually experimental chart) showing the solubilities at different temperatures.
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<span>KClO₃ is a highly soluble in water, so you do not work with Kps.
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<span>You need the solubility chart or just assume that it has the normal behavior of the most common salts. You might know from ordinary experience that you can dissolve more sodium chloride (table salt) in water when the water is hot. That is the same with KClO₃.


</span><span>The solubility chart of KlO₃ is almost a straight line (slightly curved upward), with positive slope (ascending from left to right) meaning that the higher the temperature the more the amount of salt that can be dissolved.</span>
4 0
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Read 2 more answers
Which element consists of positive ions immersed in a “sea” of mobile electrons
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Answer:

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For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80
Lostsunrise [7]

This question is describing the following chemical reaction at equilibrium:

A\rightleftharpoons B

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%}  =0.25

Thus, by recalling the Van't Hoff's equation, we can write:

ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )

Hence, we solve for the enthalpy change as follows:

\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }

Finally, we plug in the numbers to obtain:

\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}

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How do I round 10.25 to only 3 significant digits
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10.3 is good the correct rounding of three sig figures

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