Answer:
Explanation:
I am a bit confused is there instuctions on what to write on or anything like that
____________________________________________________
Answer:
Your answer would be a). 2.0 × 10-9
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Work:
In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.
You would use the ph (4.48) to find the ka for "hbro"
[H+]
=
10^-4.48
=
3.31 x 10^-5 M
=
[BrO-]
or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]
Then you would find ka:
(3.31 x 10^-5)^2/0.55 =2 x 10^-9
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<em>-Julie</em>
Since the two atoms have the same number of protons they are the same element. The fact that they have different numbers of neutrons makes them isotopes. The best answer is A.
Answer:
4.1 mol·L⁻¹
Explanation:
You are diluting the solution with water, so you can use the dilution formula
c₁V₁ = c₂V₂ Divide each side by V₂
c₂ = c₁ × V₁/V₂
Data:
c₁ = 7.0 mol·L⁻¹; V₁ = 2.5 L
Water added = 1.5 L
Calculations:
(a) <em>New volume
</em>
V₂ = 2.5 L + 1.8 L
= 4.3 L
(b) <em>New concentration
</em>
c₂ = 7.0 × 2.5/4.3
= 7.0 × 0.581
= 4.1 mol·L⁻¹
