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3 years ago

How much heat is needed warm 65.34 g of water from 18.43 to 21.75

Chemistry

1 answer:

BaLLatris [955]3 years ago

5 0

Given that

Mass of water = 65.34 g

Amount of heat = mass of water * specific heat (temperature change

)

= 65.34 g * 4.184 J / g-C ( 21.75-18.43 )C

= 907.63 J

= 0.908 KJ

And

1 cal = 4.186798 J

907.63 J * 1 cal / 4.186798 J =216.78 cal

Or0.218 kcal

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Does adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent, a lesser extent, or a greater e

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Answer:

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent by adding 1 mol of $C_06H_{12}O_6$ to 1 kg of water.

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7nadin3 [17]

Answer:

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The naming of coordination compounds follows certain rules specified by IUPAC. Usually, the name of the complex makes it quite easy to deduce its structure.

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Lastly the III that appeared after the metal name "cobalt" shows its oxidation state. The iodide counter ions must then be 3 in number in order to satisfy this primary valency of the metal hence the inclusion of I3 in the structure of the complex.

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