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Rudiy27
3 years ago
7

do clouds and wind appear to follow the same patterns? Can you find any patterns in the direction that they move?

Physics
1 answer:
aniked [119]3 years ago
6 0
What scientists use to make models of the Earth's water cycle so they can<span> see how it is ... Where </span>does<span> the water that we use to meet our everyday needs come from? .... what </span>you<span> notice about the </span>patterns<span> the</span>winds<span> and </span>clouds follow<span>: </span>Do clouds and<span> ... </span>same patterns<span>? </span>Can you find any patterns in the direction that they move? Precipitation is a vital component of how water moves through Earth’s water cycle, connecting the ocean, land and atmosphere. Water evaporates from the surface of the land and oceans, rises and cools, condenses into rain or snow, and falls again to the surface as precipitation. The water falling on land collects in rivers and lakes, soil, and porous layers of rock, and much of it flows back into the oceans. The cycling of water in and out of the atmosphere is a significant aspect of the weather patterns on Earth. so that will be probs the best i can do
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The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2
Oliga [24]

Answer:

The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2 gas. Which coefficients would be placed in front of water and oxygen?

2 in front of water and 1 in front of oxygen

Kiley wants to balance the equation H2 + N2 → NH3. Which would be her first step in balancing an equation?

NOT adding the coefficient 3 in front of H2 and the coefficient 2 in front of NH3

Which is the balanced equation for V2O5 + CaS → CaO + V2S5?

V2O5 + 5CaS → 5CaO + V2S5

One half of a balanced chemical equation is shown.

3Mg(OH)2 + 2H3PO4

Which lists the numbers of each atom the other half of the equation would contain?

3 Mg, 2 P, 14 O, 12 H

Substances A and B react in a ratio of A + B → AB. Colin was combining substance A and substance B to form substance AB. He added 10 g of substance A and 45 g of substance B.

How much of substance AB would Colin make?

55g

Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting equation?

NOT 2C4H3Br + 5O2 → 4CO2 + 2H2O + 2HBr

NOT C4H3Br + O2 → CO2 + H2O + HBr

Which best describes the law of conservation of mass?

The mass of the reactants and products is equal and is not dependent on the physical state of the substances.

6 0
3 years ago
Read 2 more answers
Find the area of the part of the plane 5x 3y z = 15 that lies in the first octant.
Lunna [17]

This part of the plane lies above a triangle with boundaries x=0 and y=0 along the coordinate axes, as well as the line

z=0 \implies 5x + 3y = 15 \implies y = \dfrac{15 - 5x}3

When y=0, we have 15-5x=0\implies x=3. So this triangle is the set

T = \left\{(x,y)\in\Bbb R^2 ~:~ 0\le x\le3 \text{ and } 0\le y\le\dfrac{15-5x}3\right\}

Also, when x=0, we have y=\frac{15}3=5. So the triangle has length 3 and width 5, hence area 1/2•3•5 = 15/2.

Let z=f(x,y) = 15 - 5x - 3y. Then the area of the plane over T is

\displaystyle \iint_T dA = \iint_T \sqrt{1 + \left(\frac{\partial f}{\partial x}\right)^2 + \left(\frac{\partial f}{\partial y}\right)^2} \, dx \, dy

We have

\dfrac{\partial f}{\partial x} = -5 \implies \left(\dfrac{\partial f}{\partial x}\right)^2 = 25

\dfrac{\partial f}{\partial y} = -3 \implies \left(\dfrac{\partial f}{\partial y}\right)^2 = 9

\implies\displaystyle \iint_T dA = \sqrt{35} \iint_T dx\,dy = \boxed{\frac{15\sqrt{35}}2}

since the integral

\displaystyle \iint_TdA

is exactly the area of T, 15/2.

8 0
2 years ago
Which statement best describes what Kendall can measure?
Vaselesa [24]

Answer + Explanation:

B

She can measure the volume and mass of the marble, the volume and mass of the water, and the mass of the graduated cylinder.




Hope This Helped :D

6 0
2 years ago
A ball whose mass is 0.4 kg hits the floor with a speed of 4 m/s and rebounds upward with a speed of 2 m/s. If the ball was in c
e-lub [12.9K]

Answer:

Explanation:

We shall apply concept of impulse

Impulse = Force x time

= Force x 2 x 10⁻³ N.s

impulse = change in momentum

change in momentum

= .4 x 4 - ( - .4 x 2 )

= 2.4

Force x 2 x 10⁻³  = 2.4

Force = 2.4 /  2 x 10⁻³

= 1.2 x 10³ N .

average magnitude of the force exerted by floor = 1.2 x 10³ N

If R be reaction force by earth

R - mg = 1.2 x 10³

R = 1.2 x 10³ + mg

= 1200 + .4 x 9.8

= 1200 +3.92

= 1203 .92 N .

7 0
3 years ago
Por que no céu sem nuvens a lua nova não é visivel e a lua cheia aparece em grande destaque?
weeeeeb [17]
Porque la matematica es imposible

4 0
3 years ago
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