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stealth61 [152]
3 years ago
7

What considerations are included in the Preliminary Floodproofing/Retrofitting Preference Matrix?

Engineering
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

D. Risk, off-site flooding, and aesthetic concerns

Explanation:

Retrofitting has to do with the change in the structure of a building after it has been occupied or constructed.

The Preliminary Floodproofing/Retrofitting Preference Matrix offers an assistance to the designer by the documentation of the initial consultation with the owner of the home.

The consideration are Risk, off-site flooding, and aesthetic concerns

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Which is the correct order for handwashing
cupoosta [38]

Answer:

Follow these five steps every time.

1.Wet your hands with clean, running water (warm or cold), turn off the tap, and apply soap.

2.Lather your hands by rubbing them together with the soap. Lather the backs of your hands, between your fingers, and under your nails.

3.Scrub your hands for at least 20 seconds. Need a timer? Hum the “Happy Birthday” song from beginning to end twice.

4.Rinse your hands well under clean, running water.

5.Dry your hands using a clean towel or air dry them.

8 0
3 years ago
Read 2 more answers
For a Cu-Ni alloy containing 53 wt.% Ni and 47 wt.% Cu at 1300°C, calculate the wt.% of the alloy that is solid and wt.% of allo
Zina [86]

Answer:

Hello your question is incomplete attached below is the complete question

answer: wt.% of alloy that is solid = 61.5%

             wt.% of allot that is liquid = 38.5%

Explanation:

To determine the wt.% of the alloy that is solid

= \frac{R}{R +S } * 100

=  \frac{53-45}{58-45} * 100  = 61.5%

To determine the wt.% of the alloy that is liquid

= \frac{S}{S+R} * 100\\

= \frac{58-53}{58-45} *100 = 38.5%

attached below is a free hand sketch as well

7 0
3 years ago
A specimen of a 4340 steel alloy with a plane strain fracture toughness of 54.8 MPa (50 ksi ) is exposed to a stress of 2023 MPa
Neko [114]

Answer:

Explanation:

The formula for critical stress is

\sigma_c=\frac{K}{Y\sqrt{\pi a} }

\sigma_c =\texttt{critical stress}

K is the plane strain fracture toughness

Y is dimensionless parameters

We are to Determine the Critical stress

Now replacing the critical stress with 54.8

a with 0.2mm = 0.2 x 10⁻³

Y with 1

\sigma_c=\frac{54.8}{1\sqrt{\pi  \times 0.2\times10^{-3}} } \\\\=\frac{54.8}{\sqrt{6.283\times10^{-4}} } \\\\=\frac{54.8}{0.025} \\\\=2186.20Mpa

The fracture will not occur because this material can handle a stress of 2186.20Mpa  before fracture. it is obvious that is greater than 2023Mpa

Therefore, the specimen does not failure for surface crack of 0.2mm

4 0
3 years ago
A three-point bending test is performed on a glass specimen having a rectangular cross section of height d = 5.4 mm (0.21 in.) a
Fudgin [204]

Answer:

5.21e-2mm

Explanation:

Please see attachment

8 0
4 years ago
Quadrature encoders operate with two photodetectors offset by _______ degrees. (a) 45 (b) 90 (c) 180 (d) 270
Lemur [1.5K]

Answer:

i think it should be 90 degree

5 0
3 years ago
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