Answer:
Explanation:
The magnitude of the acceleration in the x direction is always zero: TRUE.
At the apex, in the y direction the velocity is zero and the accelration is positive. TRUE.
At the apex, in the x direction, the velocity is zero and the acceleration is zero. FALSE. The accelration is zero, but the velocity is the same it had when it was shot.
The magnitude of the velocity in the y direction is always constant. FALSE, it's subject to gravity and it's velocity varies as 
At the apex, in the Y direction, the velocity is negative and the acceleration is zero. FALSE. Velocity is zero, Acceleration is
, towards the negative y axis
Answer and Explanation:
with reference to Einstein's theory of special relativity, the speed of an electromagnetic radiation, here, laser will not change in any inertial frame or remains same irrespective of any change in inertial frame.
Therefore, the speed of light measured in both the cases, i.e., in astronaut's reference frame and spaceship's reference frame will be equal to the speed of light in vacuum, i.e.,
.
The laser gun's speed in astronaut's reference frame is the same as the speed of the spaceship as it mounted on it, i.e., the speed of the laser gun is 200 million m/s.
The laser gun's speed measured in spaceship's reference frame will be zero, as it is mounted on the spaceship and is stationary in the spaceship's reference frame.
Answer:
ΔT = 302 °c
Explanation:
mass (m) = 4.6 g = 0.0046 kg
velocity (v) = 278 m/s
specific heat of lead (c) = 128 J/kg. °c
kinetic energy = 0.5 mx 
kinetic energy = 0.5 x 0.0046 x 
kinetic energy = 177.8 J
since all the kinetic energy is converted to thermal energy,
kinetic energy = thermal energy (E) = 177.8 J
thermal energy = m x c x ΔT
where ΔT is the temperature change
177.8 = 0.0046 x 128 x ΔT
ΔT = 177.8 / 0.59
ΔT = 302 °c
Answer:
B yes when displacement is negative
N2+3H2->2NH3
When 3 moles of H2 react, they produce 2 moles of NH3
3 moles of H2 have a mass of 2.02 g
2 moles of NH2 have a mass of 17.0 g
So when 2.02 g H2 react, they produce 17.0 g NH3
If 26.3g H2 react with a yield of 100%, we expect…
2.02g H2_____17.0gNH3
26.3g H2_____x=221gNH3
So now let’s calculate the percentage:
221gNH3_________100%
79.0gNH3_________x=79.0*100/221=35.7%