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3 years ago

7

A girl rides her scooter to school, a total distance of 4.5km. She has to slow down twice to cross busy streets, but overall the

journey takes her 0.65h. What is her average speed during the trip?

2 answers:

Whitepunk [10]3 years ago

8 0

Answer:

6.93 km/h

Explanation:

To calculate her average speed, we need the "speed" formula, which is:

average speed = distance / time

You plug in your numbers and it will give you the answer.

Speed = 4.5km/0.65hr

= 6.923 km/h

PilotLPTM [1.2K]3 years ago

3 0

Answer:

6.93 km/h

Explanation:

i looked it up hope this helps

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What is the electric potential of a 2.2 µC charge at a distance of 6.3 m from the charge? Recall that Coulomb’s constant is k =

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3 years ago

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A rocket moves upward, starting from rest with an acceleration of +30.0 m/s2 for 5.00 s. It runs out of fuel at the end of this

olchik [2.2K]

Answer:

The distance covered by the rocket after fuel ran out is $3442.04 m$

Explanation:

Given that the rocket moves with an acceleration $a=30m/s^2$

time $t=5 s$

Since the rocket starts from rest initial velocity $u=0 s$

The distance it travelled within this time is given by $s=ut+ \frac{1}{2} at^2$ $=0 \times 5+ \frac{1}{2} (30\times25)=375 m$

Velocity at this point is given by $v=u+at$

$v=0+30\times5=150m/s$

Given that at this height it runs out of fuel but travels further. Here final velocity $v=0$ (maximum height), initial velocity $u=150 m/s$ and time to zero velocity $t=\frac{v}{g} = \frac{150}{9.8} =15.3 s.$

Thus it travels $15.3 seconds$ more after fuel running out. The distance covered during this period is given

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3 years ago

A capacitor consists of two concentric cylinders. The inner cylinder has a radius of 0.001 m and the outer cylinder a radius of

AlexFokin [52]

Answer:

The capacitance is 1.75 nF

Explanation:

From the question we are given that

The inner radius is $r_{in} = 0.001$

The outer radius is $r_{out} = 0.0011 \ m$

Length of the capacitor is $L = 1m$

The dielectric constant is $Di = 2 \ for \ 0 < \phi < \pi$

The dielectric constant is $Di_2 = 4 \ for \ \pi < \phi < 2\pi$

Generally the capacitance of a capacitor can be mathematically represented as

$C = \frac{\pi \epsilon_0 Di_1 L}{ln\frac{r_{out}}{r_{in}} } + \frac{\pi \epsilon_0 Di_2L}{ln\frac{r_{out}}{r_{in}} }$

$= \frac{\pi \epsilon_0 L (Di_1 + Di_2)}{ln\frac{r_{out}}{r_{in}} }$

$= \frac{(3.142)(8.85*10^{-12})(1)(2+4)}{ln\frac{0.0011}{0.001} }$

$=1.75*10^{-9} F$

$1.75nF$

5 0

3 years ago