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Ierofanga [76]
2 years ago
9

Which of the following allows natural selection and evolution to occur?

Physics
2 answers:
leonid [27]2 years ago
6 0

Answer:

D. differences in the characteristics of individual trees

Explanation:

Natural selection and evolution can only occur if there are differences in the characteristics of individual organisms. Organisms with advantageous adaptations, such as deep roots, are more likely to survive and reproduce than organisms without the advantageous adaptations. Continuous natural selection of one trait over another causes organisms to evolve so the advantageous trait eventually becomes more common in a population.

Black_prince [1.1K]2 years ago
4 0

Answer:

i think its B

Explanation:

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If you make multiple measurements of your height, you are likely to find that the results vary by nearly half an inch in either
Lisa [10]

Answer:

Height h= 1.7 m

Explanation:

Supposing we have to find height in meter.

1 feet = 0.3048 m

1 inch = 0.0254 m

Given that:

5 feet

= 5×0.3048

= 1.524 m

and 7 inch = 7×0.0254= 0.1778 m

Therefore total height of a man in meter

5 feet 7 inch = 1.5424+0.1778 =1.7 m

Height h= 1.7 m

8 0
2 years ago
What do halo stars do differently from disk stars?
VLD [36.1K]

Answer: They orbit the galactic center with many different inclinations, while disk stars all orbit in nearly the same plane. ... They have vertical motions out of the plane, making them appear to bob up and down, but they never get "too far" from the disk.

Explanation:

6 0
2 years ago
A 50 n force is acting on a lever 1.5 m from the fulcrum balances an object 1m from the fulcrum on the other arm. what is the we
Angelina_Jolie [31]

Answer:

A 100 N force acting on a lever 2 m from the fulcrum balances an object 0.5 m from the fulcrum on. ... What is the weight of the object(in newtons)? What is its mass (in kg)? ... mass at the one end and effort arm is the distance between pivot and effort applied at the other end.

Explanation:

hpoe this helps you.

4 0
2 years ago
The masses are m1 = m, with initial velocity 2v0, and m2 = 7.4m, with initial velocity v0. Due to the collision, they stick toge
lesya [120]

Answer:

Loss, \Delta E=-10.63\ J

Explanation:

Given that,

Mass of particle 1, m_1=m =0.66\ kg

Mass of particle 2, m_2=7.4m =4.884\ kg

Speed of particle 1, v_1=2v_o=2\times 6=12\ m/s

Speed of particle 2, v_2=v_o=6\ m/s

To find,

The magnitude of the loss in kinetic energy after the collision.

Solve,

Two particles stick together in case of inelastic collision. Due to this, some of the kinetic energy gets lost.

Applying the conservation of momentum to find the speed of two particles after the collision.

m_1v_1+m_2v_2=(m_1+m_2)V

V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}

V=\dfrac{0.66\times 12+4.884\times 6}{(0.66+4.884)}

V = 6.71 m/s

Initial kinetic energy before the collision,

K_i=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)

K_i=\dfrac{1}{2}(0.66\times 12^2+4.884\times 6^2)

K_i=135.43\ J

Final kinetic energy after the collision,

K_f=\dfrac{1}{2}(m_1+m_2)V^2

K_f=\dfrac{1}{2}(0.66+4.884)\times 6.71^2

K_f=124.80\ J

Lost in kinetic energy,

\Delta K=K_f-K_i

\Delta K=124.80-135.43

\Delta E=-10.63\ J

Therefore, the magnitude of the loss in kinetic energy after the collision is 10.63 Joules.

7 0
3 years ago
A cup has a mass of 0.0650 kg and a
Roman55 [17]

Answer: 0.185

Explanation:

Trust bro

5 0
2 years ago
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