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Ierofanga [76]
3 years ago
9

Which of the following allows natural selection and evolution to occur?

Physics
2 answers:
leonid [27]3 years ago
6 0

Answer:

D. differences in the characteristics of individual trees

Explanation:

Natural selection and evolution can only occur if there are differences in the characteristics of individual organisms. Organisms with advantageous adaptations, such as deep roots, are more likely to survive and reproduce than organisms without the advantageous adaptations. Continuous natural selection of one trait over another causes organisms to evolve so the advantageous trait eventually becomes more common in a population.

Black_prince [1.1K]3 years ago
4 0

Answer:

i think its B

Explanation:

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Conduction is usually faster/slower in liquids and certain solids than in gases.
KIM [24]
Conduction is slower in liquids and gases.

Liquids it is convection which transmits more heat.. quicker...

Materials which are good conductors of thermal energy are called thermal conductors.

metals are good thermal conductors.


6 0
3 years ago
Reduce<br> Reflects<br> Transfers<br> Stops
Bond [772]
I think transfers is the answer
4 0
3 years ago
Two insulated copper wires of similar overall diameter have very different interiors. One wire possesses a solid core of copper,
Marrrta [24]

Answer:

a

 Solid Wire     I  =   0.01237 \  A      

  Stranded  Wire  I_2  =   0.00978 \  A

b

  Solid Wire   R  = 0.0149 \ \Omega

   Stranded  Wire  R_1  = 0.0189 \ \Omega

Explanation:

Considering the first question

From the question we are told that

  The  radius of the first wire is  r_1  = 1.53 mm = 0.0015 \  m

  The radius of  each strand is  r_0 =  0.306 \ mm =  0.000306 \ m

  The current density in both wires is  J  =  1750 \  A/m^2

Considering the first wire

     The  cross-sectional area of the first wire is

      A   = \pi  r^2

= >  A   = 3.142 *  (0.0015)^2

= >  A   = 7.0695 *10^{-6} \  m^2

Generally the current in the first wire is    

     I  =  J*A

=>  I  =  1750*7.0695 *10^{-6}

=>  I  =   0.01237 \  A

Considering the second wire  wire

The  cross-sectional area of the second wire is

     A_1  =  19 *  \pi r^2

=>     A_1  =  19 *3.142 *  (0.000306)^2

=>  A_1  =  5.5899 *10^{-6} \  m^2

Generally the current is  

      I_2  =  J  *  A_1

=>    I_2  =   1750  *  5.5899 *10^{-6}

=>    I_2  =   0.00978 \  A

Considering question two  

 From the question we are told that

     Resistivity is  \rho  =  1.69* 10^{-8} \Omega \cdot m

     The  length of each wire  is  l =  6.25 \  m

Generally the resistance of the first wire is mathematically represented as

    R  =  \frac{\rho *  l  }{A}

=> R  =  \frac{  1.69* 10^{-8} * 6.25 }{ 7.0695 *10^{-6} }

=> R  = 0.0149 \ \Omega

Generally the resistance of the first wire is mathematically represented as

    R_1  =  \frac{\rho *  l  }{A_1}

=> R_1  =  \frac{  1.69* 10^{-8} * 6.25 }{5.5899 *10^{-6} }

=> R_1  = 0.0189 \ \Omega

3 0
3 years ago
What is the force in N of an object that has a mass of 7 kilograms and an acceleration of 4 m/s/s
VMariaS [17]

Newton's 2nd law of motion:         Force = (mass) x (acceleration)

If you want to move a 7-kg object with an acceleration of 4 m/s²,
then you will need to push it with (7 x 4) = 28 newtons of force.

4 0
3 years ago
The diagram below shows a model of the Earth's orbit around the Sun.
Sladkaya [172]
I would say that I and IV because summer is I and fall is IV
7 0
3 years ago
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