Explanation:
Given the mass of HCl is ---- 0.50 g
The volume of solution is --- 4.0 L
To determine the pH of the resulting solution, follow the below-shown procedure:
1. Calculate the number of moles of HCl given by using the formula:

2. Calculate the molarity of HCl.
3. Calculate pH of the solution using the formula:
![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
Since HCl is a strong acid, it undergoes complete ionization when dissolved in water.

Thus, ![[HCl]=[H^+]](https://tex.z-dn.net/?f=%5BHCl%5D%3D%5BH%5E%2B%5D)
Calculation:
1. Number of moles of HCl given:

2. Concentration of HCl:

3. pH of the solution:
![pH=-log[H^+]\\=-log(0.003425)\\=2.47](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D%5C%5C%3D-log%280.003425%29%5C%5C%3D2.47)
Hence, pH of the given solution is 2.47.
Answer:
The balanced chemical equation will be "
".
Explanation:
The given equation is:

<u>Step 1:</u>
<u></u>
...(equation 1)
<u>Step 2:</u>
<u></u>
...(equation 2)
On adding "equation 1" and "equation 2", we get
⇒ 
⇒ 
The second step:
⇒ 
Answer:
λ=2167.6 nm
The wavelength of light emitted is 2167.6 nm.
Explanation:
We recall that Eₙ=
since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE
ΔE=E₄-E₇
ΔE=
ΔE=-9.1760*10^-20 J
Now:
|ΔE|=Energy of photon=h*v=h*c/λ
λ=h*c/|ΔE|
λ=
λ=2.1676*10^-6 m
λ=2167.6*10^-9 m
λ=2167.6 nm
The wavelength of light emitted is 2167.6 nm.
Where are the equations ..
Sorry....
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