Answer:
is an aqueous reactant
is a liquid product
is a gaseous product
Explanation:
⇔
Hydrogen carbonate dissocates to form carbon dioxide and water. The acid (hydrogen carbonate) is in aqueous form and it dissociates to water (liquid) and carbon dioxide (a gas). It is also seen that the hydrogen carbonate is on the reactant side and it dissociates to produce water and carbon dioxide.
W<u> is an aqueous reactant</u> (a reactant undergoes changes in a chemical reaction
<u /><u> is a liquid product</u> (product refers to the species produced from chemical reaction)
<u /><u> is a gaseous product</u>
Since the question manages to include moles, pressure, volume, and temperature, then it is evident that in order to find the answer we will have to use the Ideal Gas Equation: PV = nRT (where P = pressure; V = volume; n = number of moles; R = the Universal Constant [0.082 L·atm/mol·K]; and temperature.
First, in order to work out the questions, there is a need to convert the volume to Litres and the temperature to Kelvin based on the equation:
250 mL = 0.250 L
58 °C = 331 K
Also, based on the equation P = nRT ÷ V
⇒ P = (2.48 mol)(0.082 L · atm/mol · K)(331 K) ÷ 0.250 L
⇒ P = (67.31 L · atm) ÷ 0.250 L
⇒ P = 269.25 atm
Thus the pressure exerted by the gas in the container is 269.25 atm.
<h3>
Answer: 144 g</h3>
Explanation:
Mass of glucose = moles × molar mass
∴ Mass of glucose = 0.8 mol × 180 g mol⁻¹
= 144 g
∴ the mass of glucose you need to have 0.8 mol of glucose = 144 g
Thank you for posting your question here at brainly. The <span>mole fraction of co if the h2 mole fraction is 0.22 and the o2 mole fraction is 0.58 is 0.20, below is the solution:
</span>
mole fraction CO + mole fraction H2 + mole fraction O2 = 1
mole fraction CO = 1 - ( 0.22 + 0.58)=0.20