what is the boiling point of the element aluminum?

given a density of 350 grams/cm3 and a mass of 25 grams. What is the volume using the equation involving density?

Eduardwww [97]

0.07cm³

Explanation:

Given parameters:

Density of the body = 350g/cm³

Mass of the body = 25g

Unknown:

Volume of the body = ?

Solution:

Density is the amount of substance contained in a volume of body. It is expressed as:

Density = $\frac{mass}{volume}$

Since the unknown is volume, we make it the subject of the expression;

Volume = $\frac{mass}{density}$

Volume = $\frac{25}{350}$ = 0.07cm³

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Density brainly.com/question/2690299

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6 0

4 years ago

C3H8 + 5O2 → 3CO2+ 4H2O, if 5.75L of oxygen are consumed in the above reaction, how many L of carbon dioxide are produced?

anzhelika [568]

Answer: 3.45 L carbon dioxide are produced

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}=\frac{5.75L}{22.4L}=0.257moles$

$C_3H_8+5O_2(g)\rightarrow 3CO_2+4H_2O$

According to stoichiometry :

5 moles of $O_2$ produce = 3 moles of $CO_2$

Thus 0.257 moles of $O_2$ will produce= $\frac{3}{5}\times 0.257=0.154moles$ of $CO_2$

Volume of $CO_2=moles\times {\text {Molar volume}}=0.154moles\times 22.4L/mol=3.45$

Thus 3.45 L carbon dioxide are produced

6 0

3 years ago

Of which tissue is the dermis composed of?

Maslowich

The dermis or corium is a layer of skin between the epidermis

6 0

3 years ago

A 0.6467-g portion of manganese dioxide was added to an acidic solution in which 1.1701 g of a chloride-containing sample was di

Katen [24]

Answer:

29.39% of AlCl₃ in the sample

Explanation:

Based on the reaction:

MnO₂(s) + 2Cl⁻ + 4H⁺ → Mn²⁺ + Cl₂(g) + 2H₂O

We can find the amount of chloride in solution with the amount of MnO₂ that reacted as follows:

Initial mass MnO₂ = 0.6467g

Recovered mass = 0.3104g

Mass that reacted = 0.6467g - 0.3104g = 0.3363g

Moles MnO₂ -Molar mass: 86.9368g/mol-:

0.3363g * (1mol / 86.9368g) = 3.868x10⁻³ moles MnO₂

Moles Cl⁻:

3.868x10⁻³ moles MnO₂ * (2mol Cl⁻ / 1mol MnO₂) = 7.737x10⁻³ moles Cl⁻

Moles of AlCl₃ and mass -Molar mass AlCl₃: 133.34g/mol-:

7.737x10⁻³ moles Cl⁻ * (1mol AlCl₃ / 3mol Cl⁻) = 2.579x10⁻³ moles AlCl₃

2.579x10⁻³ moles AlCl₃ * (133.34g / mol) =

0.3439g of AlCl₃ are present in the sample.

The percent is:

0.3439g of AlCl₃ / 1.1701g * 100 =

<h3>29.39% of AlCl₃ in the sample</h3>

7 0

3 years ago

Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:

NeTakaya

Answer:

The partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C Is 0.103 atm.

The correct option is A.

Explanation;

NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°C

NH4I(s)= 0.215

NH3(g)=0.103

HI(g)Kp=0.112

Therefore = 0.103 +0.112= 0.215

Therefore the partial pressure of ammonia at equilibrium is 0.103 atm

7 0

3 years ago

﻿﻿what is the boiling point of the element aluminum?

what is the boiling point of the element aluminum?