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gavmur [86]
4 years ago
8

Donald needs to produce 5000 milliliters of 32% alcohol solution. At his disposal he has 40% alcohol solution and 20% alcohol so

lution. How much of each does he need in order to produce his desired solution?
Chemistry
1 answer:
PolarNik [594]4 years ago
8 0

Answer:

The answer to your question is 3 L of solution 40% and 2 L of solution 20%

Explanation:

Data

Final volume = Vf = 5000 ml = 5 L

Final concentration = Cf = 32%

Concentration 1 = C1 = 40%

Concentration 2 = C2 = 20%

Volume 1 = x

Volume 2 = 5 - x

Process

1.- Write an equation to solve this problem

     VfCf = C1V1 + C2V2

2.- Substitution

    32(5) = 40x + 20(5 - x)

3.- Solve for x

     160 = 40x + 100 - 20x

     160 - 100 = 40x - 20x

               60 = 20x

               60/20 = x

               x = 3

     Then, Volume 1 = 3 L

4.- Find Volume 2

     Volume 2 = 5 - 3

     Volume 2 = 2 L

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dissolves easily in water

has a high boiling point

has a high melting point

conducts electricity when melted

Explanation:

Salts are ionic compounds. Ionic compounds are formed when two atoms exchange their valence electrons. One atom gains and the other atom loses.

Generally, ionic compounds have the following properties:

  1. They are usually hard solids with high melting points or liquids with high boiling points.
  2. They are soluble in water and insoluble in non-polar solvents. This is conforms with the solubility rule that like dissolve like.
  3. In aqueous solution or molten form, ionic compounds conducts electricity.
  4. They take part in very fast chemical reactions.

Learn more:

Ionic compounds brainly.com/question/6071838

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4 years ago
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When 12.71 g of copper react with 8.000 g of sulfur, 14.72 g of copper(I) sulphide is produced. What is the percentage yield in
Citrus2011 [14]
2Cu + S = Cu₂S

n(Cu)=m(Cu)/M(Cu)
n(Cu)=12.71/63.55=0.2 mol

n(S)=m(s)/M(S)
n(S)=8.000/32.01=0.25 mol

Cu:S  2:1  
0.2 mol : 0.25 mol copper deficiency, sulphur in excess

theoretical mass of copper (I) sulfide 
m(Cu₂S)=M(Cu₂S)n(Cu)/2

the percentage yield in the reaction is
w=m'(Cu₂S)/m(Cu₂S)=2m'(Cu₂S)/M(Cu₂S)n(Cu)
w=2*14.72/(159.16*0.2)=0.925 (92.5%)

5 0
3 years ago
An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure and temperature were 94.0mL,
xeze [42]

Answer: The original volume in liters was 0.0707L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.85 atm

P_2 = final pressure of gas = 456 mm Hg = 0.60 atm   (760mmHg=1atm)

V_1 = initial volume of gas = ?

V_2 = final volume of gas = 94.0 ml

T_1 = initial temperature of gas = 66^oC=273+66=339K

T_2 = final temperature of gas = 113^oF=318K  (32^0F=273K)

Now put all the given values in the above equation, we get:

\frac{0.85\times V_1}{339}=\frac{0.60\times 94.0}{318}

V_1=70.7ml=0.0707L   (1L=1000ml)

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3 years ago
Calculate the volume in liters of a M potassium dichromate solution that contains of potassium dichromate . Round your answer to
maksim [4K]

The question is incomplete, here is the complete question:

Calculate the volume in liters of a 0.13 M potassium dichromate solution that contains 200. g of potassium dichromate . Round your answer to 2 significant digits.

<u>Answer:</u> The volume of solution is 5.2 L

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

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We are given:

Molarity of solution = 0.13 M

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Putting values in above equation, we get:

0.13M=\frac{200}{294.15\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{200}{294.15\times 0.13}=5.23L

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