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3 years ago

Throwing a football is an example of force because

Physics

1 answer:

siniylev [52]3 years ago

4 0

Answer:

i found this provided by the San Francisco 49ers (found on Khan Academy)

Explanation:

I HOPE THIS HELPS!!!

So, what is a force? A force is a push or a pull exerted on one object from another. Forces make things move. You can make something start or stop when you push or pull an object.

There are many different types of forces in action in football. A player kicking a football is a force that makes the football fly through the air. A quarterback throwing a football is another example of a force that makes the football fly in a game.

When studying the concept of force, we can look to history to find mathematical principles that guide the laws of motion. Sir Isaac Newton was one of the most famous scientists of the 17th century to study the laws of forces and motion. Through careful study of how objects react to various forces, Newton developed the Three Laws of Motion. Below are explanations of each law and how these laws can be applied to football.

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Energy in the form of motion is potential energy.<br> True<br> False

Veseljchak [2.6K]

False

Energy in the form of motion is kinetic energy

Stored energy is called potential energy

5 0

3 years ago

Which describes the changes in visible light moving from red to violet?

eimsori [14]

The wavelength decreases to roughly half.
(The frequency roughly doubles.)

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4 years ago

The eiffel tower has a mass of 7.3 million kilograms and a height of 324 meters. its base is square with a side length of 125 me

uranmaximum [27]

Since the tower base is square with a side length of 125 m,

Therefore,

$(125\ m)^2+ (125\ m)^2=31250 m^2$

Square root of 31250 = 176.776953 (Diameter) , so this is the diameter of the cylinder to enclose it, and radius, r = 88.38834765 m and height, h = 324 m.

The volume of cylinder,

$=\pi r^2h=3.14(88.38834765 m)^2\times 324 m =7948168.803\ m^3$

Thus, the mass of the air in the cylinder,

$=1.225\ kg/m^3 \times 7948168.803\ m^3=9736506.78\ kg$

Hence, the mass of the air in the cylinder is this more than the mass of the tower.

4 0

3 years ago

A leaky 10-kg bucket is lifted from the ground to a height of 11 m at a constant speed with a rope that weighs 0.9 kg/m. Initial

nalin [4]

Answer:

the work done to lift the bucket = 3491 Joules

Explanation:

Given:

Mass of bucket = 10kg

distance the bucket is lifted = height = 11m

Weight of rope= 0.9kg/m

g= 9.8m/s²

initial mass of water = 33kg

x = height in meters above the ground

Let W = work

Using riemann sum:

the work done to lift the bucket =∑(W done by bucket, W done by rope and W done by water)

= $\int\limits^a_b {(Mass of Bucket + Mass of Rope + Mass of water)*g*d} \, dx$

Work done in lifting the bucket (W) = force × distance

Force (F) = mass × acceleration due to gravity

Force = 9.8 * 10 = 98N

W done by bucket = 98×11 = 1078 Joules

Work done to lift the rope:

At Height of x meters (0≤x≤11)

Mass of rope = weight of rope × change in distance

= 0.8kg/m × (11-x)m

W done = integral of (mass×g ×distance) with upper 11 and lower limit 0

W done = $\int\limits^1 _0 {9.8*0.8(11-x)} \, dx$

Note : upper limit is 11 not 1, problem with math editor

W done = 7.84 (11x-x²/2)upper limit 11 to lower limit 0

W done = 7.84 [(11×11-(11²/2)) - (11×0-(0²/2))]

=7.84(60.5 -0) = 474.32 Joules

Work done in lifting the water

At Height of x meters (0≤x≤11)

Rate of water leakage = 36kg ÷ 11m = $\frac{36}{11}$ kg/m

Mass of rope = weight of rope × change in distance

= $\frac{36}{11}$ kg/m × (11-x)m = 3.27kg/m × (11-x)m

W done = integral of (mass×g ×distance) with upper 11 and lower limit 0

W done = $\int\limits^1 _0 {9.8*3.27(11-x)} \, dx$

Note : upper limit is 11 not 1, problem with math editor

W done = 32.046 (11x-x²/2)upper limit 11 to lower limit 0

W done = 32.046 [(11×11-(11²/2)) - (11×0-(0²/2))]

= 32.046(60.5 -0) = 1938.783 Joules

the work done to lift the bucket =W done by bucket+ W done by rope +W done by water)

the work done to lift the bucket = 1078 +474.32+1938.783 = 3491.103

the work done to lift the bucket = 3491 Joules

8 0

4 years ago

a canon is firing horizontally from the high wall of a castle located in the midst of a flat plain. if i drop a canon ball from

dsp73

D=44.13, Horizontal velocity is unimportant. The time it takes the cannon ball to fall to the ground is the key to determining the height of the cliff. where that cannon is present.

The speed of any projectile travelling along a Horizontal velocity is known as the horizontal velocity. When a particle or object is launched into the air at an angle other than 90 degrees, it moves along the trajectory path and changes the shape of the curve to a parabolic one.

the speed at which velocity changes over time. Due to its magnitude and direction, acceleration is a vector quantity. The first derivative of velocity with respect to time or the second derivative of position with respect to time are further examples. This is called acceleration.

Distance to the ground is d = 1/2gt^2,

where g is the acceleration rate of gravity (9.80665 m/s^2)

and t = 3 secs.

d = .5×9.80665×9 = 44.13 m.

Learn more about horizontal velocity here

brainly.com/question/18084516

#SPJ4

3 0

1 year ago