Answer:
The height of the cliff from which the ball was dropped from is 224.4m.
\overline{v}={\frac{\Delta x}{\Delta t}}
Given the data in the question;
Initial velocity of the ball;
Time taken by the ball to reach the ground;
Distance or Height of the cliff from which the ball was thrown from;
To get the height of the Cliff, we use the Second Equation of Motion:
Where s is the distance or height, is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;
Hence, the equation becomes
We substitute the given values into the equation
Therefore, the height of the cliff from which the ball was dropped from is 224.4m
Explanation:
