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Andreyy89
3 years ago
8

A 25.00-g sample of a solid is placed in a graduated cylinder, and then the cylinder is filled to the 50.0-mL mark with benzene.

The mass of benzene and solid together is 63.29 g. Assuming that the solid is insoluble in benzene and that the density of benzene is 0.880 g/cm^3 , calculate the density of the solid.
Chemistry
1 answer:
aliina [53]3 years ago
7 0

Answer:

solid density = 3.85 g/mL

Explanation:

First we calculate the mass of the benzene:

benzene mass = 63.29 - 25 = 38.29 g

We know that density = mass / volume

So the volume of benzene will be:

volume = mass / density

volume = 38.29 / 0.880 = 43.51 cm³ =  43.51 mL of benzene     (1 cm³ = 1 mL)

Now the volume of the sample will be:

sample volume = 50 - 43.51 = 6.49 mL

Now we can calculate the density of the solid:

density = mass / volume

solid density = 25 / 6.49 = 3.85 g/mL

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For the first ionization energy for an N2 molecule, what molecular orbital is the electron removed from
olga55 [171]

Answer:

p orbital.

Explanation:

Valence electrons are the electrons in an atom holding the very last orbital which is used in chemical bonding with other elements. Their existence could define the chemical properties of that atom.

During the first energy in ionization of an N2 molecule the molecular orbital from which the electron could be extracted is the only one with the highest energy level. Nitrogen has its outermost orbital (p) containing three valence electrons. Each orbital is only half filled, and thus it is unstable Thus, the electron mission must have been removed from p orbital.

7 0
3 years ago
2 years ago a 4.00 l flexible container holds a sample of hydrogen gas at 153 kpa. if the pressure increases to 203 kpa and the
garri49 [273]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

 

P1V1 =P2V2

 V2 = P1 x V1 / P2

 <span>V2 = 153 x 4 / 203</span>

 V2 = 3 L

7 0
3 years ago
What is the mass, in grams, of 2.50 * 10-3 mol of aluminum sulfate?
Nonamiya [84]

Answer:

The mass is 0.855 grams (option A)

Explanation:

Step 1: Data given

aluminium sulfate = Al2(SO4)3

Numer of moles Al2(SO4)3 = 2.50 * 10^-3 moles

atomic mass Al = 26.99 g/mol

atomic mass S = 32.065 g/mol

Atomic mass O = 16 g/mol

Step 2: Calculate molar mass Al2(SO4)3

Molar mass = 2* 26.99 + 3*32.065 + 12*16

Molar mas = 342.175 g/mol

Step 3: Calculate mass Al2(SO4)3

Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass Al2(SO4)3

Mass Al2(SO4)3 = 2.5 *10^-3 moles * 342.175 g/mol

Mass Al2(SO4)3 = 0.855 grams

The mass is 0.855 grams (option A)

5 0
3 years ago
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
Assuming that the smallest measurable wavelength in an experiment is 0.730 fm (femtometers), what is the maximum mass of an obje
Archy [21]
<span>1 fm = 1.0 × 10-15 meters 
</span>so
0.610<span>  fm x (1.0x10^-15 m / 1 fm)
                   = 6.1x10^-16 m</span>
so the formula is
λ = h / mu 
so,
as we know mass value so by putting
<span>m = (6.626*10^-34)/(6.1*10^-16*199)
    =</span>(6.626*10^-34)/(1213.96*<span>10^-16)
</span><span>    = 5.45 x 10^ -21 
hope thats an answer for you</span>
6 0
3 years ago
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