Answer:
p orbital.
Explanation:
Valence electrons are the electrons in an atom holding the very last orbital which is used in chemical bonding with other elements. Their existence could define the chemical properties of that atom.
During the first energy in ionization of an N2 molecule the molecular orbital from which the electron could be extracted is the only one with the highest energy level. Nitrogen has its outermost orbital (p) containing three valence electrons. Each orbital is only half filled, and thus it is unstable Thus, the electron mission must have been removed from p orbital.
To solve this we assume that the gas is an ideal
gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At
a constant temperature and number of moles of the gas the product of PV is
equal to some constant. At another set of condition of temperature, the
constant is still the same. Calculations are as follows:
P1V1 =P2V2
V2 = P1 x V1 / P2
<span>V2 = 153 x 4 / 203</span>
V2 = 3 L
Answer:
The mass is 0.855 grams (option A)
Explanation:
Step 1: Data given
aluminium sulfate = Al2(SO4)3
Numer of moles Al2(SO4)3 = 2.50 * 10^-3 moles
atomic mass Al = 26.99 g/mol
atomic mass S = 32.065 g/mol
Atomic mass O = 16 g/mol
Step 2: Calculate molar mass Al2(SO4)3
Molar mass = 2* 26.99 + 3*32.065 + 12*16
Molar mas = 342.175 g/mol
Step 3: Calculate mass Al2(SO4)3
Mass Al2(SO4)3 = moles Al2(SO4)3 * molar mass Al2(SO4)3
Mass Al2(SO4)3 = 2.5 *10^-3 moles * 342.175 g/mol
Mass Al2(SO4)3 = 0.855 grams
The mass is 0.855 grams (option A)
Answer : The final equilibrium temperature of the water and iron is, 537.12 K
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.


where,
= specific heat of iron = 560 J/(kg.K)
= specific heat of water = 4186 J/(kg.K)
= mass of iron = 825 g
= mass of water = 40 g
= final temperature of water and iron = ?
= initial temperature of iron = 
= initial temperature of water = 
Now put all the given values in the above formula, we get:


Therefore, the final equilibrium temperature of the water and iron is, 537.12 K
<span>1 fm = 1.0 × 10-15 meters
</span>so
0.610<span> fm x (1.0x10^-15 m / 1 fm)
= 6.1x10^-16 m</span>
so the formula is
λ = h / mu
so,
as we know mass value so by putting
<span>m = (6.626*10^-34)/(6.1*10^-16*199)
=</span>(6.626*10^-34)/(1213.96*<span>10^-16)
</span><span> = 5.45 x 10^ -21
hope thats an answer for you</span>