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lana [24]
3 years ago
15

Which proteins speed up chemical reactions? enzymes inhibitors amino acids

Chemistry
2 answers:
Oksana_A [137]3 years ago
5 0
Enzymes

i got this from google
Enzymes<span> are soluble protein molecules that can speed up chemical reactions in cells. These reactions include respiration, photosynthesis and making new proteins. For this reason </span>enzymes<span> are sometimes called biological catalysts</span>
Liula [17]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

An enzyme is a type of protein that acts as a catalyst which helps in speeding up a biochemical reaction in living organisms.

Whereas inhibitors are the substances that inhibit the speed of a chemical reaction. That is, inhibitors help in slow down of a chemical reaction.

The basic building blocks of proteins are known as amino acids.

Thus, we can conclude that enzymes are the proteins that speed up chemical reactions.

You might be interested in
5. Calculate the decrease in temperature when 6.00 L at 20.0 °C is compressed to 4.00 L.
Kazeer [188]

Answer: 195.3 K

Explanation: Use Charles Law to get T2

Charles Law V1 / T1 = V2 / T2

Derive the equation to find T2

T2 = V2T1 / V1

Convert temperature into K

T1 = 20.0 °C + 273 = 293 K

Substitute the values:

4.00 L x 293 K / 6.00 L = 195. 3 K

5 0
3 years ago
A solution contains some or all of the ions Cu2+,Al3+, K+,Ca2+, Ba2+,Pb2+, and NH4+. The following tests were performed, in orde
xeze [42]

Answer:

See below explanation

Explanation:

When having a mixture of metals in solution, you may perform an analytical study (using selective chemical conditions), that may help you to determine whether a metal (cation) is present or not

Using selective analytes (or conditions), leads to consecutive precipitations, until most of the cations are separated in precipitates

With this technique, you may identify metals in different groups, each group will have its analyte (or condition), which will help to have a different precipitate:

- Group I: Ag⁺, Pb⁺², Hg⁺²;  Analyte: HCL ; Precipitate: AgCl (white) , PbCl₂, HgCl₂

- Group II: As⁺³ , Bi⁺³, Cd⁺², Cu⁺² , Sb⁺³, Sn⁺² ; Analyte: H₂S (g) with HCL ; Precipitate: As₂S₃ , Bi₂S₃ , CdS (yellow) , CuS (black), Sb₂S₃, SnS

- Group III: Co⁺², Fe⁺², Fe⁺³, Mn⁺², Ni⁺², Zn⁺², Al⁺³, Cr⁺³; Analyte: NaOH or NH₃ with (NH₄)₂S (ac) ; Precipitate: CoS (black) , FeS, MnS , NiS (black), ZnS (white) , Al(OH)₃ (white), Cr(OH)₃  

- Group IV: Mg⁺², Ca⁺², Sr⁺², Ba⁺²; Analyte: Na₂CO₃ (ac) or (NH₄)₂HPO₄ (ac); Precipitate: respective carbonate or phosphate MgCO₃/MgHPO₄, CaCO₃/CaHPO₄ , SrCO₃/SrHPO₄, BaCO₃/BaHPO₄

- Group V: Li⁺, K⁺, Na⁺, Rb⁺, Cs⁺, NH₄⁺ ; will remain all in final solution

According to the original statement:

A solution contains one or more of the following: Cu⁺², Al⁺³, K⁺, Ca⁺², Ba⁺², Pb⁺², NH₄⁺

1) Addition on HCl 6M produces no change: we can say the sample does not contain Pb⁺² (group I)

2) Addition of H₂S with 0.2 M HCL produced a black solid: we could say sample contains Cu⁺²(group II)

3) Addition of (NH₄)₂HPO₄ in NH₃ produces no reaction: we could say we don´t have Ca⁺² and /or Ba⁺²  (group IV)

4) The final supernatant, when heated produced a purple flame: in the final solution, we have K⁺ (group V), which produces a purple flame (based on its characteristic emission spectrum when subjected to flame)

This analysis will be inconclusive for NH₄⁺ (according to above describe technique)

6 0
3 years ago
Susan needs to simplify the expression shown below what should be her first step
Digiron [165]
Susan should follow PEMDAS,

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction,

So, the first step should be, to solve the equation in the parentheses.

I hope this helps!
5 0
3 years ago
What is the lowest temperature a human can survive?
algol [13]
Suprysingly , Humans can survive weather well since we wear clothing.
A good estimate of how cold a human can survive would be in the range of -50 or lower.
HOPE IT HELPS!
3 0
3 years ago
How many grams of Mg(ClO3)2 are needed to make 1,500 mL of a 2.5 N solution ?​
yarga [219]

Answer:

33

Explanation:

3 0
2 years ago
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