Molecules inside a liquid _____.
2 answers:
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Answer :
(1) The mass of silver nitrate is, 555 g
(2) The solubility of the gas will be, 0.433 g/L
<u>Solution for Part 1 :</u>
From the given data we conclude that
In 100 gram of water, the amount of silver nitrate = 222 g
In 250 gram of water, the amount of silver nitrate =
Therefore, the mass of silver nitrate is, 555 g
<u>Solution for Part 2 :</u>
Formula used : (at constant temperature)
where,
= initial solubility of methane gas = 0.026 g/L
= final solubility of methane gas
= initial pressure of methane gas = 1 atm
= final pressure of methane gas = 0.06 atm
Now put all the given values in the above formula, we get the solubility of methane gas.
Therefore, the solubility of the gas will be, 0.433 g/L
Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at
.
Explanation:
Given : Mass of oxygen = 0.023 g
Volume = 31.6 mL
Convert mL into L as follows.
Temperature =
As molar mass of is 32 g/mol. Hence, the number of moles of
are calculated as follows.
Using the ideal gas equation calculate the pressure exerted by given gas as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the value into above formula as follows.
Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at
.