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cestrela7 [59]
3 years ago
8

Consider these chemical equations. N2(g) + 3H2(g) → 2NH3(g) C(s) + 2H2(g) → CH4(g) 4H2(g) + 2C(s) + N2(g) → 2HCN(g) + 3H2(g) Whi

ch equation(s) do you need to reverse in order to calculate the overall equation for the formation of HCN and H2 from NH3 and CH4? Check all that apply. N2(g) + 3H2(g) mr003-1.jpg 2NH3(g) C(s) + 2H2(g) mr003-2.jpg CH4(g) 4H2(g) + 2C(s) + N2(g) mr003-3.jpg 2HCN(g) + 3H2(g) What must you do before adding the equations?
Chemistry
2 answers:
DaniilM [7]3 years ago
8 0
The first and the second one .  . . . . . . . . . 
joja [24]3 years ago
3 0
Multiply the second equation by 2
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For a particular isomer of C 8 H 18 , the combustion reaction produces 5099.5 kJ of heat per mole of C 8 H 18 ( g ) consumed, un
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Answer:

the standard enthalpy of formation of this isomer of C₈H₁₈ (g) =  -375 kj/mol

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Heat of reaction or enthalpy of combustion = -5099.5 kj/mol

from equation (1)

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Using equation (2)

ΔH⁰f(C₈H₁₈) = -621 kj/mol

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3 years ago
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