Answer:
A u = 0.36c B u = 0.961c
Explanation:
In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains
u ’= (u-v) / (1- uv / c²)
Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory
The data give is u ’= 0.43c and the initial core velocity v = 0.94c
Let's clear the speed with respect to the observer (u)
u’ (1- u v / c²) = u -v
u + u ’uv / c² = v - u’
u (1 + u ’v / c²) = v - u’
u = (v-u ’) / (1+ u’ v / c²)
Let's calculate
u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)
u = 0.51c / (1 + 0.4042)
u = 0.36c
We repeat the calculation for the other piece
In this case u ’= - 0.35c
We calculate
u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)
u = 1.29c / (1- 0.329)
u = 0.961c
Answer:
Explanation:
As we know that the magnitude of electric field intensity is given as
now we know that intensity of the wave is given as the product of energy density and speed of the wave
so intensity is the energy flow per unit area per unit of time
so the energy that flows through the area of 0.0259 m^2 in 11.7 s is given as
We have centripetal acceleration = 
So, v = 
Now by equation of motion we have S= ut +0.5a
S =displacement, u = initial velocity, a= acceleration and t = time
Here S = 2r and a = g , u = 0
Distance traveled in horizontal direction = 
Answer:
because there is many places for it to bounce of of creating another soundwave
