Answer: At the point when space experts take a gander at an article's range, they can decide its arrangement dependent on these frequencies. The most well-known technique stargazers use to decide the sythesis of stars, planets, and different articles is spectroscopy. This spread-out light is known as a range.
Explanation:
Answer:
Explanation:
<u>1) Data:</u>
a) Hypochlorous acid = HClO
b) [HClO} = 0.015
c) pH = 4.64
d) pKa = ?
<u>2) Strategy:</u>
With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.
<u>3) Solution:</u>
a) pH
b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)
c) Equilibrium constant: Ka = [ClO⁻] [H₃O⁺] / [HClO]
d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M
e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M
f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46
Answer:
pH

OH- concentration 28.84
Explanation:
KOH dissociates into K+ and OH-. The ratio of K+ and OH- ion is 1:1
In any aqueous solution, the H3O+ and OH - must satisfy the following condition -
![[ H_3O^+] [OH^-] = k_w](https://tex.z-dn.net/?f=%5B%20H_3O%5E%2B%5D%20%5BOH%5E-%5D%20%3D%20k_w)
![[ H_3O^+] = \frac{k_w}{ [OH^-]}](https://tex.z-dn.net/?f=%5B%20H_3O%5E%2B%5D%20%3D%20%5Cfrac%7Bk_w%7D%7B%20%5BOH%5E-%5D%7D)
M
pH =
![- log [ H_3O^+]\\- log [2.857 * 10^{-13}]](https://tex.z-dn.net/?f=-%20log%20%5B%20H_3O%5E%2B%5D%5C%5C-%20log%20%5B2.857%20%2A%2010%5E%7B-13%7D%5D)
pH
![= - [-12.54]\\= 12.54](https://tex.z-dn.net/?f=%3D%20-%20%5B-12.54%5D%5C%5C%3D%2012.54)
pOH
pH
pOH

OH concentration 
OH- concentration 28.84
The name given to the anion of this ionic compound is that it would be called D. Permanganate. This is MnO4^-.
Answer: Option (a) is the correct answer.
Explanation:
Subscript present in chemical formula of a compound represents the number of atoms of the element actually present in it.
For example, in
the subscripts present in it are 7, 7, 1, and 2.
A subscript is not responsible for determining the relative mass of each type of an atom because a subscript simply represents the number of atoms of each type of an element participating or combining with other atoms of a compound.
Thus, we can conclude that the statement subscripts represent the relative mass of each type of atom in the compound, is false.