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Kisachek [45]
3 years ago
9

Two upwards forces act: one of 34N which is 3.5m to the left of the axle, the other is 25N and is 2.6m to the right of the axle.

There is also a 10N force to the left which is 0.80m below the axle.
Physics
1 answer:
KiRa [710]3 years ago
5 0

Answer:

See explanation below

Explanation:

In this case, you want to know if you put an object between these forces, which direction would go.

To know this, we need to calculate the moment of an object, which is defined as the product of a force and it's distance. In other words:

M = F * d   (1)

And, in order to reach equilibrium the force will exert a direction in clockwise or anticlosewise, and these moments, should be even:

anticlockwise moment = clockwise moment.

The clockwise would be the forces to the right, and anticlock would the only force to the left of the axle.

Clockwise moment = (10 * 0.8) + (25 * 2.6) = 73 Ns

Anticlockwise moment = 34 * 3.5 = 119 Ns.

As we can see, the moment in the anticlockwise is higher than the actual clockwise moment, therefore, we can assume that the object will move anticlockwise, or simply move to the left.

Hope this helps

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hichkok12 [17]

Answer:

The final temperature is T2= 5.35°C

Explanation:

Apply the Gay-lussacs's law we have

\frac{P1}{T1} = \frac{P2}{T2}

P1, initial pressure= 5.00 x 10^6 Pa

T1, initiation temperature= 25.°C

P2, final pressure= 1.07 x 10^6 Pa

T2, final temperature= ?

\frac{5.00 * 10^6}{25} =\frac{1.07 *10^6}{T2} \\

Cross multiplying and making T2 subject of formula we have

T2 =\frac{1.07 *10^6*25}{5.00 * 10^6} \\\\T2= \frac{26.75}{5} \\T2= 5.35

T2= 5.35°C

6 0
3 years ago
7. A scientist studying a squid observes that the squid at rest
Rzqust [24]

The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.              

We can calculate the average force with the average acceleration as follows:

F = m\overline{a}   (1)

Where:

  • m: is the mass of water = 0.60 kg
  • \overline{a}: is the average acceleration

The <em>average acceleration</em> is given by the change of velocity in an interval of time

\overline{a} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}}   (2)

Where:

  • v_{i}: is the initial velocity = 0 (the squid is at rest)
  • v_{f}: is the final velocity = 15.0 m/s
  • t_{i}: is the initial time = 0  
  • t_{f}: is the final time = 0.15 s

Now we can find the <em>average force</em> after entering equation (2) into (1)

F = m(\frac{v_{f} - v_{i}}{t_{f} - t_{i}}) = 0.60 kg(\frac{15.0 m/s - 0}{0.15 s}) = 60 N  

Therefore, the average force on the squid during the propulsion is 60 N.

Find more about average force here:

  • brainly.com/question/20902034
  • brainly.com/question/12916904

I hope it helps you!

3 0
3 years ago
An electron moving horizontally to the right with speed v enters a region where a uniform magnetic field exists pointing into th
koban [17]

Answer:

W = 0

Explanation:

When an electron moves perpendicular to a uniform B-field. If the field is in a vacuum, the magnetic field B is the dominant factor determining the motion. Since the magnetic force F is perpendicular to the direction of travel, an electron follows a curved path in a magnetic field. The electron continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force F is always perpendicular to velocity v, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.

W = F*d*Cos ∅ = F*d*Cos 90° = 0  where d is the displacement.

The pic shown can help to understand the explanation.

5 0
3 years ago
Which term describes the point when two objects reach the same temperature and there is no longer a transfer of energy through h
yaroslaw [1]
The term you need to know is equilibrium. Technically it means that heat gained = heat lost. Normally in beginning chemistry classes the evidence for this condition is a stable temperature. 
5 0
3 years ago
Can someone help me please :( ASAP. Also I’m sorry if it’s small
Umnica [9.8K]

Answer:

Graph #2

Explanation:

Notice, on the position time graph, there is a constant rate of change. This means that there is a constant velocity, meaning it's a straight line. The line is decreasing so the velocity will be negative.

3 0
3 years ago
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