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3 years ago

A bug walking on the circular rim of a flower

Physics

1 answer:

Mekhanik [1.2K]3 years ago

8 0

Given parameters;

Time taken to complete a lap = 8.667s

Radius of flower = 13.9cm

convert to SI unit of m, 100cm = 1m

13.9cm gives $\frac{13.9}{100}$ = 0.139m

Unknown = speed

To solve this problem, we need to first find the circumference of the flower.

Circumference of the circular flower = 2 π r

where r is the radius of the flower;

Circumference = 2 x 3.142 x 0.139 = 0.87m

Now to find the how fast the bug is travelling,

Speed = $\frac{distance}{time}$

Since the bug covered 1 lap, the distance is 0.87m

Now input the parameters and solve for speed;

Speed = $\frac{0.87}{8.667}$ = 0.1m/s

The bug is travelling at a speed of 0.1m/s

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tankabanditka [31]

Answer:

$80 m/s^2$

Explanation:

The acceleration of an object is given by:

$a=\frac{v-u}{t}$

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For the rocket in this problem,

u = 20,000 m/s

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Answer:

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Explanation:

The current magnitude of current is given by the resistance and the induced Emf as:

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3 years ago

• How much work is required to lift a 2kg object 2m high?

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Answer You need to consider that the gravity on earth is 9.8 m/s/s. This means any object you let go on the earths surface will gain 9.8 m/s of speed every second. You need to apply a force on the object in the opposite direction to avoid this acceleration. If you are pushing something up at a constant speed, you are just resisting earths acceleration. The more massive and object is, the greater force is needed to accelerate it. The equation is Force = mass*acceleration. So for a 2kg object in a 9.8 m/s/s gravity you need 2kg*9.8m/s/s = 19.6 Newtons to counteract gravity. Work or energy = force * distance. So to push with 19.6 N over a distance of 2 meters = 19.6 N*2 m = 39.2 Joules of energy. There is an equation that puts together those two equations I just used and it is E = mgh

The amount of Energy to lift an object is (mass) * (acceleration due to gravity) * (height)

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Which of the following is true about a planet orbiting a star in uniform circular

Mnenie [13.5K]

The velocity vector of the planet points toward the center of the circle is the following is true about a planet orbiting a star in uniform circular motion.

A. The velocity vector of the planet points toward the center of the circle.

Explanation:

Motion of the planet around the star is mentioned to be uniform and around a circular path. Objects in uniform circular motion motion has constant angular speed but the velocity of the object will not remain constant. Since the planet is in circular motion the direction of velocity vector at a particular point is tangential to the circular path at that particular point.

Thus at every point, the direction of velocity vector changes and this means the velocity is never constant. The objects in uniform circular motion has centripetal acceleration which means that velocity vector of the planet points toward the center of the circle.

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