A bug walking on the circular rim of a flower

Physics

1 answer:

Mekhanik [1.2K]2 years ago

8 0

Given parameters;

Time taken to complete a lap = 8.667s

Radius of flower = 13.9cm

convert to SI unit of m, 100cm = 1m

13.9cm gives $\frac{13.9}{100}$ = 0.139m

Unknown = speed

To solve this problem, we need to first find the circumference of the flower.

Circumference of the circular flower = 2 π r

where r is the radius of the flower;

Circumference = 2 x 3.142 x 0.139 = 0.87m

Now to find the how fast the bug is travelling,

Speed = $\frac{distance}{time}$

Since the bug covered 1 lap, the distance is 0.87m

Now input the parameters and solve for speed;

Speed = $\frac{0.87}{8.667}$ = 0.1m/s

The bug is travelling at a speed of 0.1m/s

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Read 2 more answers

You have an incident ray from a medium with a n1=1, through a medium with a n2 =3.325. If the incident angle is equal to 0.478 r

sesenic [268]

Answer:

0.139 rad

Explanation:

We use Snell's law $n_1sin\theta_1=n_2sin\theta_2$ , where if $n_1$ is the refractive index of the medium containing the incident ray, $\theta_1$ would be the incident angle, and if $n_2$ is the refractive index of the medium containing the refracted ray, $\theta_2$ would be the refraction angle, which we want, so we do: