You have a sealed glass jar full of air. If you put it in the freezer, what happens to the gas pressure in the jar?

A 0.40-kg mass is attached to a spring with a force constant of k = 277 N/m, and the mass–spring system is set into oscillation

valentina_108 [34]

To solve this problem it is necessary to apply the concepts related to the kinetic energy expressed in terms of simple harmonic movement, as well as the concepts related to angular velocity and acceleration and linear acceleration and velocity.

By definition we know that the angular velocity of a body can be described as a function of mass and spring constant as

$\omega = \sqrt{\frac{k}{m}}$

Where,

k = Spring constant

m = mass

From the given values the angular velocity would be

$\omega = \sqrt{\frac{277}{0.4}}$

$\omega = 26.31rad/s$

The kinetic energy on its part is expressed as

$E = \frac{1}{2} m\omega^2A^2$

Where,

A = Amplitude

$\omega$ = Angular Velocity

$m = Mass$

PART A) Replacing previously given values the energy in the system would be

$E = \frac{1}{2} m\omega^2A^2$

$E = \frac{1}{2} (0.4)(26.31)^2(3*10^{-2})^2$

$E= 0.1245J$

PART B) Through the amplitude and angular velocity it is possible to know the linear velocity by means of the relation

$v = A\omega$

$v = (3*10^{-2})(26.31)$

$v = 0.7893m/s$

PART C) Finally, the relationship between linear acceleration and angular velocity is subject to

$a = A\omega^2$

$a = (3*10^{-2})(26.31)^2$

$a = 20.76m/s^2$

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Transmission is the passing of a wave through SOMEthing.

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What happens when a star's core runs out of hydrogen and why does this occur?

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When the core runs out of hydrogen to fuse, then it starts fusing the helium. This happens because a star cannot create more hydrogen.

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Physical Properties include...

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and C. taste, odor, and texture

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