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Fynjy0 [20]
3 years ago
5

Explain the difference between impulse and impulsive force?

Physics
1 answer:
ExtremeBDS [4]3 years ago
7 0
An impulsive force is a force that is acting only during a short time, I mean, for an instant. Impulse is a physics magnitude define by the product of the impulsive force and the time that it was acting.

Is there any mistake in my English? Please, let me know.
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I believe it’s gas because that’s all that stars are really made of
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9. When a balloon rises into the air, it
Ksenya-84 [330]

Answer:

Answer 3: When a balloon goes up higher in the air, its size will increase. Since there's less air in the upper atmosphere, there's less stuff pushing back on the balloon, and hence the pressure is lower, which allows the balloon to expand

Answer: C

Explanation:

As the balloon rises, the gas inside the balloon expands because the atmospheric pressure surrounding the balloon drops. The atmosphere is 100 to 200 times less dense at the float altitudes than on the ground. and as the air is heated inside the balloon it causes it to rise upwards (because it is lighter than the cooler air on the outside). When the pilot needs to bring the balloon down again, he simply reduces the temperature of the air inside the balloon causing it to slowly descend.

4 0
2 years ago
The level of water in an olympic size swimming pool (50.0 meters long, 25.0 meters wide, and about 2.00 meters deep) needs to be
Goshia [24]
<span>We need to start by finding the surface area of the pool.
50 meters multiplied by 25 meters gives us 1250 square meters.
1250 square meters multiplied by .065 (6.5 cm in meters) gives us a volume of 81.25 cubic meters of water that needs to be pumped out of the pool.

There are 1000 liters in a cubic meter so this is 81250 liters. Divide by 4.2 to find the number of seconds required to pump out this much water and we get 19345.2 seconds. This equals approximately 5.37 hours.</span>
4 0
3 years ago
Sound travels at a speed of about 340m/s in the air. How long will it take an explosion to be heard from a distance of 20 miles
Goryan [66]

First convert the speed of sound from meters/second to miles/second:

340\,\dfrac{\mathrm m}{\mathrm s}\cdot\dfrac{3.281\,\mathrm{ft}}{1\,\mathrm m}\cdot\dfrac{1\,\mathrm{mi}}{5280\,\mathrm{ft}}=0.21\,\dfrac{\mathrm{mi}}{\mathrm s}

Then the time it takes for the sound to travel 20 miles is

\dfrac{20\,\mathrm{mi}}{0.21\,\frac{\mathrm{mi}}{\mathrm s}}=95\,\mathrm s

3 0
3 years ago
An alpha particle collides with an oxygen nucleus, initially at rest. The alpha particle is scattered at an angle of 25.0° above
Greeley [361]

Answer:

v_{i}= 19\times 10^5\ m/s

Explanation:

given,

scattering angle of alpha particle = 25.0°  above its initial direction of motion

oxygen nucleus recoils at = 50.0° below this initial direction.

final speed of the oxygen = 2.08×10⁵ m/s

mass of alpha particle = 4.0 u

mass o oxygen nucleus = 16 u

momentum conservation along x- axis

m_{a}v_{i} = m_a v_a cos\theta + m_o v_o cos\theta

4v_{i} = 4\times v_a cos25^0 + 16\times 2.08 \times 10^5 cos50^0

v_{i}= \dfrac{3.625\times v_a+ 21.39\times 10^5}{4}....(1)

Along y-direction

0 = m_av_a sin \theta - m_ov_o sin\theta

0 = 4\times v_a sin 25 - 16\times  2.08 \times 10^5 sin50^0

v_a = \dfrac{25.49 \times 10^5}{1.69}

v_a = 15.082\times 10^5\ m/s

putting value in equation (1)

v_{i}= \dfrac{3.625\times 15.082\times 10^5+ 21.39\times 10^5}{4}

v_{i}= 19\times 10^5\ m/s

5 0
3 years ago
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