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Len [333]
3 years ago
9

If energy is transferred spontaneously as heat from a substance with a temperature of T1 to a substance with a temperature of T2

, which of the following statements must be true?
1-T1 < T2

2-T1 = T2

3-T1 > T2

4-more information is needed
Physics
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer: The statement T_{1} > T_{2} must be true.

Explanation:

As it is given that heat is being transferred from a substance with temperature T_{1} to a substance with temperature T_{2}.

It is known that heat will always being transferred from a higher temperature to a lower temperature. Because at higher temperature the molecules of a substance acquire more energy and when they lose energy then a decrease in temperature occurs.

Hence, in the given situation T_{1} > T_{2}.

Thus, we can conclude that the statement T_{1} > T_{2} must be true.

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A. 112 J

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When a wave is acted upon by an external damping force, what happens to the energy of the wave
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A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/
s344n2d4d5 [400]

Answer:

At t = (70 / 3) \; {\rm s} (approximately 23.3 \; {\rm s}.)

Explanation:

Note that the acceleration of the car between t = 0\; {\rm s} and t = 20\; {\rm s} (\Delta t = 20\; {\rm s}) is constant. Initial velocity of the car was v_{0} = 0\; {\rm m\cdot s^{-1}}, whereas v_{1} = 35\; {\rm m\cdot s^{-1}} at t = 20\; {\rm s}\!. Hence, at t = 20\; {\rm s}\!\!, this car would have travelled a distance of:

\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}.

At t = 20\; {\rm s}, the truck would have travelled a distance of x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}.

In other words, at t = 20\; {\rm s}, the truck was 400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m} ahead of the car. The velocity of the car is greater than that of the truck by 35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}. It would take another (50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s} before the car catches up with the truck.

Hence, the car would catch up with the truck at t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}.

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1 year ago
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cause of the g force pushing u back

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The mass of a string is 5.9 × 10-3 kg, and it is stretched so that the tension in it is 200 n. a transverse wave traveling on th
bagirrra123 [75]

The velocity of the wave on the string is given by

v=\sqrt{\frac{T}{\frac{m}{L}}}  \\  v=\sqrt{\frac{TL}{m}}

Solving the above equation,

v^2=\frac{TL}{m} \\  L=\frac{v^2m}{T}

The frequency of the wave f=300 and wave length is 0.76

The velocity is v=(300)(0.76)=228

Substituting numerical values,

L=\frac{228^2(0.0059)}{200}\\ T=1.534

The length of the string is 1.534 m

4 0
3 years ago
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