In order to calculate the percent of water in the hydrate, we need to know the amount of water that is lost after heating. We simply subtract the initial amount and the final amount. We do as follows:
mass of water = 15.60 g - 8.63 g = 6.97 g
Percent water = 6.97 / 15.60 x 100 = 44.68%
Bromine, sodium hydroxide, sulfuric acid and hydrogen peroxide
The friction force
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The answer is Potential,
An energy possess by an object by virtue of its position. OR the energy an object has at a stationary position
Answer: please find attached to see the structure.
1. THE STRUCTURE OF BENZOIC ACID AND FLUORENE, soluble in ether and insoluble in water.
2. THE STRUCTURE OF CARBOXYLIC ACID BEEN EXTRACTED.
Explanation: the mixture of benzoic acid and fluorene are the first diagrams which shows the carboxylic acid attached to the benzene ring, which are soluble in ether and insoluble in water. When dissolved in NaOH(aq) is the carboxy ion becomes soluble in water but insoluble in ether, this is seen in the second diagram.
The third diagram shows the carboxylic acid been precipitated and soluble in ether but insoluble in water.
NOTE THE TWO MAIN DIAGRAM IS THE FIRST AND THE LAST DIAGRAM, WHERE CARBOXYLIC ACID DISSOLVES IN AQUEOUS SODIUM HYDROXIDE, AND WHEN THE ACID IS BEEN PRECIPITATED IN AQUEOUS HCl.
ALSO NOTE THE CHANGE IN BENZOIC RING MIXED WITH FLUORENE TO THAT OF THE ACID BEEN EXTRACTED.
Hope together with the picture, this has helped you.