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Zigmanuir [339]
3 years ago
6

Which of these waves can NOT travel through the vacuum of space?

Physics
1 answer:
Leno4ka [110]3 years ago
3 0
Sound waves <span>can NOT travel through the vacuum of space?</span>
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a man is trying to move a piano by himself, but it will not move, what force must they overcome to start the piano moving?
m_a_m_a [10]

Answer:

The friction of the piano and the weight

Explanation:

7 0
3 years ago
What's it called when a liquid changes to a solid
r-ruslan [8.4K]

Answer:

solidification

Explanation:

8 0
3 years ago
What must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-
sergey [27]

q = -21 * 10^{-6} C

<h3>What is Free-fall acceleration?</h3>

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 m/s at sea level on the Earth.

As we know that charge and its sign that remains in equilibrium is under gravity must be such that it will balance the gravitational force by electric force,

mg =qE

1.45 * 10^{-3}(9.80)=q(600)\\\\q = 21 *10^{6} C\\\\

and its sign must be negative so that it will have upward electric force

so it is

q = -21 * 10^{-6} C

The charge of a particle of mass is -21 * 10^{-6} C

Learn more about Free-fall acceleration: brainly.com/question/2165771

#SPJ1

8 0
2 years ago
Living organisms increase in complexity as they grow, resulting in a decrease in the entropy of an organism. How does this relat
svet-max [94.6K]

Answer:

C: As a consequence of growing, organisms cause a greater increase in entropy in their environment than the decrease in entropy associated with their growth.

Explanation:

Particularly, whole organisms on the earth obtain the energy from sunlight, and the sun is undertake an vast increase in entropy that simply compensates for the reducing entropy of living things on this small planet.

8 0
3 years ago
A flat, 181 ‑turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 4.97 cm2 and the angle
Sidana [21]

Answer:

B = 0.135T

Explanation:

To find the magnitude of the magnetic field you use the following formula, for the torque produced by a magnetic field B in a loop:

\tau=NIABsin\theta   (1)

τ: torque = 1.51*10^-5 Nm

I: current = 2.47mA = 2.47*10^-3 A

B: magnitude of the magnetic field

A: area of the loop = 4.97cm^2 = 4.97(10^-2m)^2=4.97*10^-4m^2

N: turns = 181

θ: angle between B and the magnetic dipole (same as the direction  of the normal to the plane)

You replace the values of the parameters in (1). Furthermore you do B the subject of the formula:

B=\frac{\tau}{NIAsin\tetha}=\frac{1.51*10^{-5}Nm}{(181)(2.47*10^{-3}A)(4.97*10^{-4}m^2)(sin30.1\°)}=0.135T

3 0
3 years ago
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