Answer:
The distance traveled by the woman is 34.1m
Explanation:
Given
The initial height of the cliff
yo = 45m final, positition y = 0m bottom of the cliff
y = yo + ut -1/2gt²
u = 20.0m/s initial speed
g = 9.80m/s²
0 = 45.0 + 20×t –1/2×9.8×t²
0 = 45 +20t –4.9t²
Solving quadratically or by using a calculator,
t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s
So this is the total time it takes for the ball to reach the ground from the height it was thrown.
The distance traveled by the woman is
s = vt
Given the speed of the woman v = 6.00m/s
Therefore
s = 6.00×5.69 = 34.14m
Approximately 34.1m to 3 significant figures.
The geosphere interacts with the hydrosphere when water causes rock to erode. The atmosphere provides the geosphere with heat and energy for erosion, and the geosphere reflects the sun's energy back into the atmosphere.
Answer:
0
Explanation:
the momentum will always be 0 when it is at rest because the object isnt moving!
Hope this helped!
Answer:
The gazelles top speed is 27.3 m/s.
Explanation:
Given that,
Acceleration = 4.2 m/s²
Time = 6.5 s
Suppose we need to find the gazelles top speed
The speed is equal to the product of acceleration and time.
We need to calculate the gazelles top speed
Using formula of speed
![v=at](https://tex.z-dn.net/?f=v%3Dat)
Where, v = speed
a = acceleration
t = time
Put the value into the formula
![v=4.2\times6.5](https://tex.z-dn.net/?f=v%3D4.2%5Ctimes6.5)
![v=27.3\ m/s](https://tex.z-dn.net/?f=v%3D27.3%5C%20m%2Fs)
Hence, The gazelles top speed is 27.3 m/s.