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4 years ago

14

It is said that using a lever trades a large force over a small force for a small force over a longer distance. Explain how this

makes lifting things easier

2 answers:

tatuchka [14]4 years ago

7 0

You can apply force to a large area

lilavasa [31]4 years ago

5 0

You can apply force to a large area over the fulcrum to have it multiplied on a smaller area on the other side of the fulcrum.

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Which TWO correctly relate the attraction between the particles of a liquid and the temperature at which the liquid changes stat

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A and C because stronger attractions means it needs more energy to break them so a higher temperature is needed

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3 years ago

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a roller coaster has a mass of 275kg. it sits at the top of a hill with a height 85m if it drops from this hill, how fast is it

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4 years ago

In this case, lithium would be classified as a(n)<br><br>A)atom.B)compound.C)ion.D)molecule.

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4 years ago

What are the units used to measure specific heat capacity?.

Nuetrik [128]

The units used to measure specific heat capacity is Joules per kilogram per Kelvin.

<h3>What is specific heat capacity?</h3>

It is the amount of heat absorbed per kilogram of material when the temperature rises by 1 kelvin.

Specific heat capacity C is the Joules of energy in form of heat per kilogram per Kelvin temperature. The units represented by

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3 years ago

Richard is driving home to visit his parents. 135 mi of the trip are on the interstate highway where the speed limit is 65 mph .

Elis [28]

<h2>Answer:</h2>

He saves 13.2 minutes

<h2>Explanation:</h2>

Hey! The question is incomplete, but it can be found on the internet. The question is:

How many minutes did he save?

Let's call:

$t_{1}:Time \ at \ speed \ 65mph \\ \\ t_{2}:Time \ at \ speed \ 73mph \\ \\ v_{1}=65mph \\ \\ v_{2}=73mph$

We know that the 135 miles are on the interstate highway where the speed limit is 65 mph. From this, we can calculate the time it takes to drive on this highway. Assuming Richard maintains constant the speed:

$v=\frac{d}{t} \\ \\ d:distance \\ \\ t:time \\ \\ v:velocity \\ \\ t_{1}=\frac{d}{v_{1}} \\ \\ t=\frac{135}{65} \\ \\ t_{1}=2.07 \ hours$

Today he is running late and decides to take his chances by driving at 73 mph, so the new time it takes to take the trip is:

$t_{2}=\frac{135}{73} \\ \\ t_{2}=1.85 \ hours$

So he saves the time $t_{s}$ :

$t_{s}=t_{1}-t_{2}=2.07-1.85=0.22 \ hours$

In minutes:

$t_{s}=0.22h\left(\frac{60min}{1h}\right) \\ \\ \boxed{t_{s}=13.2min}$

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3 years ago