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Arturiano [62]
3 years ago
12

Calculate in witch material - sodium or zinc sulphide is the highest percentage by mass of sulfur ​

Chemistry
1 answer:
rjkz [21]3 years ago
5 0

Answer:

sodium sulphide.

Explanation:

First, let us obtain the percentage of sulphur in both compounds. This is illustrated below:

For sodium sulphide(Na₂S):

Molar Mass of Na₂S = (23x2) + 32 = 46 + 32 = 78g/mol

Percentage of sulphur in Na₂S is given by:

32/78 x 100 = 41%

For zinc sulphide(ZnS):

Molar Mass of ZnS = 65.4 + 32 = 97.4g/mol

Percentage of sulphur in ZnS is given by:

32/97.4 x 100 = 33%

From the results obtained sulphur has the highest percentage by mass in sodium sulphide.

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Can someone help me on this letter E please
raketka [301]
I think it’s Carbon dioxide
5 0
3 years ago
Determine the limiting reactant (lr) and the mass (in g) of nitrogen that can be formed from 50.0 g n2o4 and 45.0 g n2h4. some p
Licemer1 [7]
                                                   N2O4(l) + 2 N2H4(l) → 3 N2(g) + 4 H2O(g)
1) to calculate the limiting reactant you need to pass grams to moles.
<span> moles is calculated by dividing mass by molar mass
</span>
mass of N2O4: 50.0 g 
molar mass of <span>N2O4 = 92.02 g/mol
</span><span>molar mass of N2H4 = 32.05 g/mol.
</span>mass of N2H4:45.0 g

moles N2O4=50.0/92.02 g/mol= 0,54 mol of N2O4
moles N2H4= 45/32.05 g/mol= 1,40 mol of <span><span>N2H4

</span> 2)</span>
By looking at the balanced equation, you can see that 1 mol of N2O4 needs 2 moles of N2H4 to fully react . So to react  0,54 moles of N2O4, you need 2x0,54 moles of <span>N2H4 moles
</span><span>N2H4 needed = 1,08 moles.
You have more that 1,08 moles </span><span>N2H4, so this means the limiting reagent is not N2H4, it's </span>N2O4. The molecule that has molecules that are left is never the limiting reactant.

3) 1 mol of N2O4 reacting, will produce 3 mol of N2 (look at the equation)
There are 0,54 mol of N2O4 available to react, so how many moles will produce of N2?
1 mol N2O4------------3 mol of N2
0,54 mol N2O4--------x
x=1,62 mol of N2

4) the only thing left to do is convert the moles obtained, to grams.
We use the same formula as before, moles equal to mass divided by molar mass.
moles= \frac{grams}{molar mass}             (molar mass of N2= 28)
1,62 mol of N2= mass/ 28
mass of N2= 45,36 grams

4 0
3 years ago
Assume that coal can be represented by the chemical formula C135H96O9NS. If 4.0 tons of coal is burned, what mass of nitrogen is
Schach [20]

Answer:

0.02 tons of NO produced when 4 tons of coal is burned

Explanation:

From the given,

Chemical formula of coal =  C_{134}H_{96}O_{9}NS

Molecular mass of coal = (134\times12)+(9\times1)+(9\times16)+14+32\,=1906.1gm

Let’s calculate the mass of nitrogen in coal

Percentage\,weight\,of\,nitrogen=\frac{Mass\,of\,nitrogen}{Molecular\,mass\,of coal}

Percentage\,weight/,of/,nitrogen=\frac{14}{1906.1}=0.73%

Amount of coal burnt = 4tons

Amount of NO produced by burning 4tons = 4\,tons\,of\,coal\times \frac{0.73tons}{100\,tons\,of\,coal}=0.0292\,tons

This nitrogen is converted into NO by reacting with atmospheric oxygen.

8 0
3 years ago
Read 2 more answers
Before we can use this equation for
AlexFokin [52]

Answer:

2C₂H₆ +  [7]O₂     →      [4]CO₂ + [6]H₂O

Explanation:

Chemical equation:

C₂H₆ +  O₂     →      CO₂ + H₂O

Balanced chemical equation:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Step 1:

2C₂H₆ +  O₂     →      CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C = 1

H = 12                                    H = 2

O = 2                                     O = 3

Step 2:

2C₂H₆ +  O₂     →      4CO₂ + H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 2

O = 2                                     O = 9

Step 3:

2C₂H₆ +  O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 2                                     O = 14

Step 4:

2C₂H₆ +  7O₂     →      4CO₂ + 6H₂O

Left hand side                      Right hand side

C = 4                                     C =  4

H = 12                                    H = 12

O = 14                                     O = 14

3 0
3 years ago
Unscramble dreor to get a science answer
lesantik [10]
Order. 
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5 0
3 years ago
Read 2 more answers
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