Planets stay in orbit because of the gravitational pull of the Sun. Hope this helps
Answer:
Explanation:
Convert the mass to kg:
375g = 375/1000kg = 0.375kg
F = ma
-20 = 0.375a
a = -20/0.375
a = -53
The object is accelerating at 53m/s/s backwards assuming that the forward motion is positive.
Answer: V-final= {F*{d/v¹}} /{m1 + m2}
Explanation: From Newton's second law we know that impulse that is force multiplied by time is equal to change in momentum.
Therefore the momentum before collision would be
F*t
But time t = distance (d)/velocity(V1)
t = d/V1
Momentum before collision
=F * {d/v1}.
Also, from the question we were told after collision the two balls stuck together. That statement means that they move with a common ( same) velocity after collision.
Therefore,
Momentum after collision
= {m1+m2}*V-final
From the law of conservation of momentum which state that the sum of momentum before collision is EQUAL to the momentum after collision. We have that,
F*{d/v1} = {m1+m2}*V-final
Making V- final subject of the formula we have that,
V-final = {F*{d/v1}} / {m1+m2}
NOTE: The momentum of a body is the product of it's mass and velocity. That is M* V.
A. Medium 1 is air. The refractive index of air is 1.0003. Refractive index is a measure of the bending of a ray of light when passing from one medium to another. If i is the angle of incidence of a ray in vacuum and r is the angle of refraction, the refractive index n is defined as the ratio of the sine angle of incidence to the sine of the angle of refraction; that is, n= sin i/ sin r. Refractive index may also be given by the velocity of light in medium 1 divided by the velocity of light in medium 2.
b. In this case the refractive index = sin 72.5/sin 39.6
= 1.4962
but n = x/ 1.0003 = 1.4962
Therefore; x = 1.4967
Hence the refractive index of medium 2 is 1.4967.
I therefore think that medium 2 is toluene; since it has a similar refractive index.
Answer:
The change in momentum of the car is 16380.8 kg.m/s
Explanation:
Given;
mass of the car, m = 1600 kg
time of motion, t = 4.20s
force of friction on the car, F = 3900 N
final velocity of the car after the brakes were applied, v = 0
The initial velocity of the car during the motion is calculated as;
The change in momentum of the car is calculated as;
ΔP = mu
ΔP = 1600 x 10.238
ΔP = 16380.8 kg.m/s