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dybincka [34]
4 years ago
12

Orbit is gravity pulling an object into a curved path as it attempts to fly off in a straight line .

Physics
2 answers:
blagie [28]4 years ago
8 0
True think of it like a satellite if it weren't for the earths gravity they would've kept going in a straight line up 
joja [24]4 years ago
7 0
The answer would be true
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During which phase of mitosis do the chromosomes line up across the center of the cell?
nirvana33 [79]
Metaphase; the centromeres of  duplicated chromosomes line up in the middle of the cell. (It's also the shortest phase of mitosis).
5 0
3 years ago
Which in is it Speed (S) or Velocity (V)?
Andrej [43]

Explanation:

Speed has only magnitude.

Velocity has magnitude and direction.

"A bike goes 25 m/s toward  main street."

This includes a direction, so it is velocity (V).

"A person walks 4 mph."

This has only magnitude, so it is speed (S).

"A plane flies 200 m/s."

This has only magnitude, so it is speed (S).

"A bird flies 100 mph due south."

This includes a direction, so it is velocity (V).

8 0
3 years ago
Carbon dioxide enters an adiabatic nozzle steadily at 1 MPa, 518 oC, and mass flow rate of 5,322 kg/h and exits the system at 96
Orlov [11]

Answer:

The velocity at the nozzle at inlet V_{1} = 3584 \frac{m}{sec}

Explanation:

Pressure at inlet P_{1} = 1 × 10^{6} Pa

Temperature at inlet T_{1} = 518 ° c = 791 K

Mass flow rate = \frac{5322}{60} \frac{kg}{sec} = 88.7

Gas constant for carbon die oxide is R = 189 \frac{J}{kg k}

Mass flow rate inside the nozzle is given by the formula = \frac{P_{1} }{R T_{1} } × A_{1} × V_{1}

⇒ P_{1} = = 1 × 10^{6} Pa

⇒ RT_{1} = 791 × 189 = 149499 \frac{J}{kg}

⇒ A_{1} = 0.0037 m^{2}

Put all the above values in above formula we get,

⇒ 88.7 = \frac{10^{6} }{149499} × 0.0037 × V_{1}

⇒ V_{1} = 3584 \frac{m}{sec}

This is the velocity at the nozzle at inlet.

3 0
3 years ago
Halogen is most likely to react to what
arsen [322]
Halogens therefore react most vigorously with Group 1 and Group 2 metals of all main group elements.
4 0
3 years ago
In a nuclear reactor 1 g of mass is converted into energy. How much energy in Joules is produced?
KengaRu [80]

Answer:

3 x 10^5  J

Explanation:

mass of substance, m = 1 g = 0.001 kg

Velocity of light, c = 3 x 10^8 m/s

According to the Einstein mass energy equivalence, the energy associated with the mass is given by

E = m c^2

E = 0.001 x 3 x 10^8

E = 3 x 10^5  J

5 0
4 years ago
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