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konstantin123 [22]
2 years ago
9

Two forces pull on an object at the same time. Their resultant force is least when the angle between the forces is _________. A.

0° B. 45° C. 90° D. 180°
Physics
2 answers:
expeople1 [14]2 years ago
6 0
.................................c
Norma-Jean [14]2 years ago
3 0

Two forces pull on an object at the same time. Their resultant force is least when the angle between the forces is 180°.

Answer: Option D

<u>Explanation:</u>

When two forces are acting on an object, two possibilities are there.

(i) Forces acting on the same direction.

(ii) Forces acting o the opposite direction.

When two forces are acting on the same direction, their resultant force will be maximum, but when they are acting on the opposite direction, minimum resultant force will be the outcome (i.e) they are 180 degrees apart.

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Three sticks are arranged to form a right triangle. If the lengths of the three sticks are 0.47 m, 0.62 m and 0.78 m, what are t
Svetradugi [14.3K]

The angles in the triangle are 91 degrees, 53 degrees and 36 degrees respectively.

<h3>What is the cosine rule?</h3>

From the cosine rule we know that;

c^2 = a^2 + b^2 - 2abcosC

Since;

a = 0.47 m

b =  0.62 m

c =  0.78 m

Then;

(0.78)^2 = (0.47)^2 + (0.62)^2 - 2(0.47 * 0.62)cosC

0.61 = 0.22 + 0.38 - 0.58 cosC

0.61 - ( 0.22 + 0.38) = - 0.58 cosC

0.01 = - 0.58 cosC

C = cos-1(0.01/-0.58)

C = 91 degrees

Using the sine rule;

b/Sin B = c/Sin C

0.62/sinB = 0.78/sin 91

0.62/Sin B = 0.78

B = sin-1 (0.62//0.78)

B = 53 degrees

Angle A is obtained from the sum of angles in a triangle;

180 - (91 + 53)

A = 36 degrees

Learn more about triangle:brainly.com/question/2773823

#SPJ1

6 0
1 year ago
If a student flicks a stationary 0.1 kg ball with 5N of force for 0.1 seconds. What is its final
Alisiya [41]

5m/s

Explanation:

Given parameters:

Mass of ball = 0.1kg

Force on the ball = 5N

time taken = 0.1s

Unknown:

final speed of the ball = ?

Solution:

According to newton's second law "the net force on a body is the product of its mass and acceleration".

  Force = mass x acceleration      equation 1

Acceleration =

  V is the final velocity

  U is the initial velocity

  T is the time taken

 U = O since it is a stationary body;

      a = \frac{V}{T}

Input "a" into equation 1

  F = m x \frac{V}{T}

 5 = 0.1 x \frac{V}{0.1}

 V = 5m/s

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

3 0
3 years ago
A 0.0100-kilogram grape hangs from a vine 1.50 meters from the ground. What is the potential energy of the grape?
ludmilkaskok [199]
The potential energy is defined as Ep=m*g*h where m is the mass of the body, g=9.81 m/s² and h is the height of the body. In our case m=0.01 kg and h=1.5 m. So when we input the values into the equation:

Ep=0.01*9.81*1.5= 0.14715 J. 

So the potential energy of a grape is Ep=0.14715 J. 
8 0
3 years ago
Read 2 more answers
A pebble is thrown into a calm lake, ripples are formed from the center and move outward. The water particles in the lake travel
Misha Larkins [42]

Answer: The option (C) is correct. The energy travels horizontally.

Explanation: When the pebble is thrown into a calm lake, there will be disturbance in the lake. The ripples are formed from the center and move outward because the energy is carried out from particle to particle.

The distribution of the energy among the particles starts from center and it will carry out outward. This disturbance will occur horizontally.

Therefore, the energy travels horizontally.

7 0
3 years ago
In 0.414 s, a 8.86-kg block is pulled through a distance of 4.36 m on a frictionless horizontal surface, starting from rest. The
Lena [83]

Answer: x = 0.957 m

Explanation:

F = ma

d = ½at²

a = 2d/t²

F = m2d/t²

F = kx

kx = m2d/t²

x = 2md/kt²

x = 2(8.86)(4.36) / (471(0.414²))

x = 0.957036...

3 0
3 years ago
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