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garri49 [273]
3 years ago
6

Consider a bent molecule, such as H2Se, in which the central atom has two lone pairs of electrons. The electronegativities of H

and Se are 2.1 and 2.4, respectively. Based on these values and on consideration of molecular geometry, the H-Se bond can be considered almost ________ and the molecule is ________.
Chemistry
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

Based on these values and on consideration of molecular geometry, the H-Se bond can be considered almost _____non-polar___ and the molecule is __polar_____.

Explanation:

Looking at the difference in electro negativity of the two elements; hydrogen and selenium, one may be led to the conclusion that the molecule is nonpolar since the magnitude of electronegative between the two bonding atoms is minimal.

However, electro negativity difference alone is insufficient to determine the polarity of a molecule. The structure of the molecule is also considered. Based on the structure of the molecule, it is expected to have a dipole moment. Hence the molecule is polar.

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What is the partial pressure of argon, par, in the flask? express your answer to three significant figures and include the appro
monitta
Given which are missing in your question:
the flask is filled with 1.45 g of argon at 25 C° 
So according to this formula (Partial pressure):
PV= nRT
first, we need n, and we can get by substitution by:
n =  1.45/mass weight of argon
   = 1.45 / 39.948 = 0.0363 mol of Ar
we have R constant = 0.0821
and T in kelvin = 25 + 273 = 298
and V = 1 L
∴ P * 1 = 0.0363* 0.0821 * 298 = 0.888 atm

3 0
3 years ago
Write a balanced chemical equation for the standard formation reaction of solid sodium orthosilicate
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Equation for the standard formation of solid sodium orthosilicate:
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8 0
4 years ago
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A balloon is filled with 30L of helium gas at 1atm.What is the volume when balloon rises to an attitude where the pressure is on
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Answer:

V_2=120L

Explanation:

Hello!

In this case, since Helium is undergoing a volume-pressure change, according the Boyle's law, we infer the following equation is used:

P_1V_1=P_2V_2

Thus, since we are not given the volume at 0.25 atm, we can solve for V2 to do so:

V_2=\frac{P_1V_1}{P_2}

Thus, we plug in to obtain:

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7 0
3 years ago
Determine the freezing point depression of 2 kg of water when 2 mol salt is added to it. The kf of water is 1.86 degrees C/M. Sh
Svet_ta [14]

Answer: The freezing point depression is 1.86^0C

Explanation:

Depression in freezing point is given by:

\Delta T_f=K_f\times m

\Delta T_f = Depression in freezing point

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m= molality = \frac{\text {moles of solute}}{\text {mass of solvent in kg}}=\frac{2mol}{2kg}=1m

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\Delta T_f=1.86^0C  

Thus freezing point depression is 1.86^0C

3 0
3 years ago
You wish to make a 0.339 m h2so4 solution from a stock solution of 12.0 m h2so4. how much concentrated acid must you add to obta
Alex_Xolod [135]
When preparing diluted solutions from concentrated solutions , we can use the following equation;
c1v1 =c2v2
Where c1 and v1 are the concentration and volume of the concentrated solution
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Substituting the values;
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8 0
4 years ago
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