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miv72 [106K]
3 years ago
15

What is the result of rock’s poor ability to transmit heat?

Chemistry
1 answer:
Anastaziya [24]3 years ago
7 0

It is a thermal insulator because it doesn’t transfer heat.

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If the fugacity of a pure component at the conditions of an ideal solution is 40 bar and its mole fraction is 0.4, what is its f
yaroslaw [1]

Answer : The fugacity in the solution is, 16 bar.

Explanation : Given,

Fugacity of a pure component = 40 bar

Mole fraction of component  = 0.4

Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.

Now we have to calculate the fugacity in the solution.

Formula used :

f_i=X_i\times f_i^o

where,

f_i = fugacity in the solution

f_i^o = fugacity of a pure component

X_1 = mole fraction of component

Now put all the give values in the above formula, we get:

f_i=0.4\times 40\text{ bar}

f_i=16\text{ bar}

Therefore, the fugacity in the solution is, 16 bar.

4 0
3 years ago
1. Find the masses of the following amounts.
In-s [12.5K]

The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of  3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

<h3>What is Mole ?</h3>

A mole is a very important unit of measurement that chemists use.

A mole of something means you have 6.023 x 10 ²³ of that thing.

  • For 2.15 mol of hydrogen sulphide (H₂S) :

1 mole hydrogen sulphide (H₂S) = 34.08088 grams

Therefore,

2.15 mol of hydrogen sulphide (H₂S) = 34.08088 grams x 2.15 mol

                                                              = 73.272 gm

  • For 3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) ;

1 mol of lead(II) iodide, (PbI₂) = 461.00894 grams

Therefore,

3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) = 461.00894 grams x 3.95 × 10⁻³ mol

                                                                  = 1.82 gm

Hence,The mass of 2.15 mol of hydrogen sulphide (H₂S) will be 73.272 gm and the mass of  3.95 × 10⁻³ mol of lead(II) iodide, (PbI₂) will be 1.82 gm

Learn more about mole here ;

brainly.com/question/21323029

#SPJ1

7 0
2 years ago
What is the mass in grams of 2.6 moles of angelic acid?
Dennis_Churaev [7]

Answer:

260.34g

Explanation:

First, you need to know what angelic acid is comprised of. It is written as C₅H₈O₂.

In order to solve for the mass of 2.6 moles of angelic acid, you need the mass of 1 mole of angelic acid. This can be found by adding the masses from the periodic table, like shown below:

5 carbon atoms = (5)(12.01g) = 60.05g

8 hydrogen atoms = (8)(1.01) = 8.08g

2 oxygen atoms = (2)(16) = 32g

angelic acid = 60.05 + 8.08 + 32 = 100.13g

Then, set up a basic stoichiometric equation and solve. The units should cancel out.

(\frac{2.6mol}{1} )(\frac{100.13g}{1mol} )=260.34g

5 0
3 years ago
A solution is prepared by mixing the 50 mL of 1 M NaH2PO4 with 50 mL of 1 M Na2HPO4. On the basis of the information, which of t
barxatty [35]

Answer:

A. PO43-

Explanation:

in the given is buffer . so H2PO4- and HPO42- both are present with equal concentration . Na+ is spectator ion it is also present in the concentration higher than the given species above .

but PO4-3 is not present . so it is lowest concentration

4 0
3 years ago
Covalent bonding involves the sharing of electrons to create a full valence shell, and
Leno4ka [110]
True. Covalent bonds involve sharing electrons to create a full valence shell.
8 0
2 years ago
Read 2 more answers
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