K=1400*V^2/2
K=20000*25^2/2. => 1400*V^2/2=20000*25^2/2 <=> 1400*V^2=20000*25^2
14*V^2=200*225
v^2=100*225/7
v=250/7^(1/2)
Answer: 250*7^(1/2)/7
Calculate velocity at halfway to the ground.
vfinal = root 2ad
v = root (2*9.81m/s^2*25)
v = 69.367175234 m/s
Kinetic energy = 1/2mv^2
Kinetic energy = 1/2 * (69.367175234 m/s^s^2
Ek = 2405.9025 Joules
Answer:
d. the same within the uncertainty of each measurement method
Explanation:
The density of an object and in general any physical property, has the same value regardless of the method used to measure it, either directly or indirectly. Since two completely different valid methods are used, the results must be the same, taking into account the level of precision of each of the methods.
I think the correct answer from the choices listed above is option A. The process of conduction is described by the heat energy is transferred from the land to the air by direct contact. Conduction is the process of heat transfer that happens through the collisions between molecules.
Hence,
<span>∆H = ∆U + W </span>
<span>=> </span>
<span>W = ∆H - ∆U </span>
<span>= -5074 kJ - (-5084.) kJ </span>
<span>= 10 kJ</span>
