Question

How many copper atoms are in a 70g copper

Answer 1

Answer:

$x = 6.634\times 10^{23}\,atoms$

Explanation:

The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:

$x = \left(\frac{70\,g}{63.546\,\frac{g}{mol}} \right)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)$

$x = 6.634\times 10^{23}\,atoms$

Answer 2

Answer:

6.64x10^23 atoms.

Explanation:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This implies that 1 mole of Cu also contains 6.02x10^23 atoms.

1 mole of Cu = 63.5g

If 63.5g of Cu contains 6.02x10^23 atoms,

Then 70g of Cu will contain = (70x6.02x10^23) /63.5 = 6.64x10^23 atoms.

Therefore, there are 6.64x10^23 atoms in 70g oh Cu