Acceleration = (change in speed) / (time for the change)
Change in speed = (speed at the end) minus (speed at the beginning.
The cart's acceleration is
(0 - 2 m/s) / (0.3 sec)
= ( -2 / 0.3 ) (m/s²) = -(6 and 2/3) m/s² .
Newton's second law of motion says
Force = (mass) x (acceleration) .
For this cart: Force = (1.5 kg) x ( - 6-2/3 m/s²)
= ( - 1.5 x 20/3 ) (kg-m/s²)
= - 10 newtons .
The force is negative because it acts opposite to the direction
in which the cart is moving, it causes a negative acceleration,
and it eventually stops the cart.
Answer:
a = 0.154 [m/s^2]
Explanation:
To solve this problem we must use the following formula of kinematics.
where:
Vf = final velocity = 0
Vi = initial velocity = 100 [km/h]
t = time = 3 [min] = 180 [s]
Now we need to convert the velocity from [km/h] to [m/s]
![100[\frac{km}{h} ]*1000[\frac{m}{1km} ]*1[\frac{h}{3600s} ]=27.77[\frac{m}{s} ]](https://tex.z-dn.net/?f=100%5B%5Cfrac%7Bkm%7D%7Bh%7D%20%5D%2A1000%5B%5Cfrac%7Bm%7D%7B1km%7D%20%5D%2A1%5B%5Cfrac%7Bh%7D%7B3600s%7D%20%5D%3D27.77%5B%5Cfrac%7Bm%7D%7Bs%7D%20%5D)
0 = 27.77 - (a*180)
a = 0.154 [m/s^2]
Note: the negative sign of the equation shows, that the car slows down until it stops
Answer:
Explanation:
If dropped from a position of rest, the object will be traveling 9.8 m/s (approximately 10 m/s) at the end of the first second, 19.6 m/s (approximately 20 m/s) at the end of the second second, 29.4 m/s (approximately 30 m/s) at the end of the third second
Answer:
<h2>3.00m high</h2>
Explanation:
Gravitational potential energy of the diver is expressed mathematically as
P = mgh
m = mass of the diver (in kg)
g = acceleration due to gravity (in m/s²)
h = the height of the diver above the water surface.
Given m = 85.0kg, g = 9,8m/s² and P = 2.50x10³ Joules, wecan determine how high the diver is above the water surface bu substituting the given values into the formula;
h = P/mg
h = 2.50x10³/85*9.8
h = 2500/833
h ≈ 3.00m
The diver is 3.00m above the water surface.
