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3 years ago

Scientists have measured the distance between the Earth and the Moon by reflecting a beam of laser

Physics

1 answer:

FrozenT [24]3 years ago

5 0

Answer:

a)speed of light.

a)speed of light×time=distance.

Explanation:

light has a constant speed of 299,792,458m/s

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HELP ASAP!!

andriy [413]

Answer:

This is false becuase different object weigh different

Thank you!

Explanation:

3 0

3 years ago

Which of the following would be the best thermal conductor?

Elis [28]

The best thermal conductor is b. metal

4 0

3 years ago

Read 2 more answers

The higher u hold something above the ground? A. The less potential B. The more kinetic energy it has C. The more potential ener

fredd [130]

I think is B or C

maby is C

6 0

4 years ago

Read 2 more answers

A spring is mounted horizontally, with its left end fixed. A spring balance attached to the free end and pulled toward the right

malfutka [58]

Answer:

200 N/m

20 rad/s

0.31415 seconds

3.18309 Hz

Explanation:

m = Mass of glider = 0.5 kg

x = Displacement of spring

F = Force on spring = 6 N

From Hooke's law we have relation

$F=kx\\\Rightarrow k=\frac{F}{x}\\\Rightarrow k=\frac{6}{0.03}\\\Rightarrow k=200\ N/m$

The spring constant is 200 N/m

Angular frequency is given by

$\omega=\sqrt{\frac{k}{m}}\\\Rightarrow \omega=\sqrt{\frac{200}{0.5}}\\\Rightarrow \omega=20\ rad/s$

The angular frequency is 20 rad/s

Frequency is given by

$f=\frac{\omega}{2\pi}\\\Rightarrow f=\frac{20}{2\pi}\\\Rightarrow f=3.18309\ Hz$

The frequency is 3.18309 Hz

Time period is given by

$T=\frac{1}{f}\\\Rightarrow T=\frac{1}{3.18309}\\\Rightarrow T=0.31415\ s$

The time period is 0.31415 seconds

6 0

3 years ago

Yo-Yo man releases a yo-yo from rest and allows it to drop, as he keeps the top end of the string stationary. The mass of the yo

patriot [66]

To solve this problem it is necessary to use the conservation equations of both kinetic, rotational and potential energy.

By definition we know that

$KE + KR = PE$

Where,

KE =Kinetic Energy

KR = Rotational Kinetic Energy

PE = Potential Energy

In this way

$\frac{1}{2} mv^2 +\frac{1}{2} I\omega^2 = mgh$

Where,

m = mass

v= Velocity

I = Moment of Inertia

$\omega =$ Angular velocity

g = Gravity

h = Height

We know as well that $\omega = v/r$ for velocity (v) and Radius (r)

Therefore replacing we have

$\frac{1}{2} mv^2 +\frac{1}{2} I\omega^2 = mgh$

$[tex]h= \frac{1}{2} \frac{v^2}{g} +\frac{1}{2} \frac{I}{mg}(\frac{v}{r})^2$ [/tex]

$h= \frac{1}{2}v^2 ( \frac{1}{g} +\frac{I}{mg}\frac{1}{r^2} )$

$h= \frac{1}{2}0.75^2 ( \frac{1}{9.8} +\frac{2.9*10^{-5}}{(0.056)(9.8)}\frac{1}{(0.0064)^2} )$

$h = 0.3915m$

Therefore the height must be 0.3915 for the yo-yo fall has a linear speed of 0.75m/s

6 0

3 years ago