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Masja [62]
3 years ago
9

A road with a radius of 75.0 m is banked so that a car can navigate the curve at a speed of 15.5 m/s without any friction. When

a car is going 22.4 m/s on this curve, what minimum coefficient of static friction is needed if the car is to navigate the curve without slipping?
Physics
1 answer:
kirza4 [7]3 years ago
8 0

Answer: 0.683

Explanation: The relationship between a car moving along a curve and the frictional force is given below as

us×g = v²/r

Where us = coefficient of static friction =?, g = acceleration due to gravity = 9.8 m/s², v = 22.4 m/s and r = 75m

By substituting the parameters, we have that

us×9.8 = 22.4²/ 75

us ×9.8 = 501.76/75

us ×9.8 = 6.690

us = 6.690/9.8 = 0.683

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Without the wheels, a bicycle frame has a mass of 8.29 kg. Each of the wheels can be roughly modeled as a uniform solid disk wit
trapecia [35]

Answer:

69.66 Joule

Explanation:

mass of bicycle frame, mf = 8.29 kg

mass of wheel, mw = 0.820 kg

radius, r = 0.343 m

velocity, v = 3.6 m/s

There are two wheels in the bicycle.

There are two types of kinetic energy of the system one is kinetic energy of rotation and another is rotational kinetic energy.

K = \frac{1}{2}m_{f}v^{2}+ 2\times \frac{1}{2}m_{w}v^{2}+ 2\times \frac{1}{2}I_{w}\omega^{2}

K = \frac{1}{2}m_{f}v^{2}+m_{w}v^{2}+ \frac{1}{2}\times m_{w}v^{2}

K = \frac{1}{2}m_{f}v^{2}+ \frac{3}{2}\times m_{w}v^{2}

K = \frac{1}{2}\times 8.29\times 3.6^{2}+ \frac{3}{2}\times 0.820\times 3.6^{2}

K = 69.66 J

3 0
3 years ago
“I am sure I will get a good grade on this project. I’ve worked really hard; my teacher will recognize my efforts!” This stateme
Pachacha [2.7K]
The answer would be b., individualism. Femininity is obviously out the picture and decentralization means "The transfer of authority from central to local government. and collectivism is "<span>the practice or principle of giving a group priority over each individual in it." And since the statement says "...my teacher will recognize MY efforts!" and not OUR efforts, then it isn't collectivism.</span>
4 0
3 years ago
Read 2 more answers
A simple electric motor consists of a 220-turn coil, 4.4 cm in diameter, mounted between the poles of a magnet that produces a 9
Verdich [7]

Answer:

M = 5.01\ A.m^2          

Explanation:

It is given that,

Number of turns in the coil, N = 220

Diameter of the coil, d = 4.4 cm

Radius of the coil, r = 2.2 cm = 0.022 m

Magnetic field produced by the poles of magnet, B=96\ mT=96\times 10^{-3}\ T

Current flowing in the coil, I = 15 A

Let M is the coil's magnetic dipole moment. Its formula is given by :

M=N\times I\times A

M=220\times 15\times \pi (0.022)^2

M = 5.01\ A.m^2

So, the coil's magnetic dipole moment is 5.01\ A.m^2. Hence, this is the required solution.

4 0
2 years ago
We measure the loudness of sound in decibels.<br> a. True<br> b. False
Tatiana [17]

Answer: The correct answer is True.

Explanation:

Loudness of sound is referred to how soft or loud a sound is for the listener.

This term is measured in a unit known as decibels referred to as dB.

This unit is used to measure the relative intensity of sounds on a scale from zero to 100 dB.

More the value of decibels, it will be uncomfortable for a person to hear that sound.

So Yes, the loudness of sound is measured in decibels.

7 0
3 years ago
A resonance tube can be used to measured the speed of sound in air. A tuning fork is held above the opening of the tube and stru
LenaWriter [7]

Answer:

330.24 Hz

Explanation:

Given:

Frequency, f = 320 Hz

L1 = 25.8 cm

L2 = 78.4 cm

L3 = 131.1 cm

Let the wavelength be λ

Then, L1 which is the length of the column of air is  λ/4.

λ/4 = 25.8 cm

λ = 25.8 × 4 = 103.2 cm = 1.032 m

Then, speed of sound in air is:

v = λ f

⇒ v = 1.032 × 320 Hz

⇒ v = 330.24 m/s

7 0
3 years ago
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