Answer:
T=138 °C
Explanation:
Given that
m = 0.028 kg
Net work output W= 60 KJ
T₂=2T₁
As we know that efficiency of Carnot heat engine given as
η = 0.5
We know that
Qa=heat addition
W= net work output
Qa= 120 KJ
From first law
Qa= W+ Qr
Qr= 120 - 60
Qr= 60 KJ
Qr Is the heat rejection.
Heat rejection per unit mass
Qr=60 / 0.028 = 2142.85 KJ/kg
Qr= 2142.85 KJ/kg
Temperature at which latent heat of steam is 2142.85 KJ/kg will be our answer.
T=138 °C
The temperature corresponding to 2142.85 KJ/kg will be 138 °C.
T=138 °C
It is when you don’t give up and you stand for your rights
Answer:
<em>c. The tension in the cord connected to the truck is greater than 1200 lb</em>
<em>e. The normal force between A and B is 1200 lb.</em>
Explanation:
The correct question should be
A 1000 lb boulder B is resting on a 200 lb platform A when truck C accidentally accelerates to the right (truck in reverse). Which of the following statements are true (select two answers)?
A free body diagram is shown below.
The normal force between the the boulder and the platform will be the sum of the force, i.e 1000 lb + 200 lb = 1200 lb
For the combination of the bodies to accelerate upwards, then the tension must be greater than the normal force, i.e T > 1200 lb
Answer:
modify temperature is lower than by the 0.196 %
Explanation:
given data
D = 250 mm
d = 0.1 mm
v = 0.5 m/s
V = 50 m/s
D = 150 mm
d = 0.1 mm
v = 0.3 m/s
V = 25 m/s
solution
first we get here initial coating condition for temperature change ΔT is
ΔT = A \times D^{1/4} \times d^{3/4}\times \frac{V}{v}^{1/2} ...............1
put here value for both condition
ΔT = A \times 250^{1/4} \times 0.1^{3/4}\times \frac{50}{0.5}^{1/2}
ΔT = 7.07 A ......................2
and
ΔT = A \times 150^{1/4} \times 0.1^{3/4}\times \frac{25}{0.3}^{1/2}
ΔT = 5.68 A .......................3
so here percentage change is
percentage change =
percentage change = - 0.196
so that modify temperature is lower than by the 0.196 %
<u>Answer:</u>
<u>of 150 pounds per square inch</u>
Explanation:
Note that the unit for measuring water pressure is called <u> pounds per square inch (psi)</u>
In the case of sprinklers and standpipe systems, a pressure <u>of 150 pounds per square inch</u> was used initially.