The answer is fusion. hope this helps!
Answer:
The answer to your question is: 303g of CO2
Explanation:
Data
mass CO2 = ?
mass C4H10 = 100 g
MW C4H10 = 58.12 g
MW CO2 = 44.01 g
Solve this problem using rules of three
Reaction
2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H20 (l)
2(58.12) ------------------ 8(44.01)
100g ------------------- x
mass of CO2 produced = x = (100)(8)(44.01) / (2)(58.12)
x = 35208 / 116.24
x = 302.9 g ≈ 303 g of CO2
Determine the number of moles of citric acid.
n of citric acid = (30 mL)(1 L / 1000 mL)(1 mol/L)
= 0.03 mol of citric acid
It is seen in the equation that each mole of citric acid reacts with 3 moles of baking soda.
n of baking soda = (0.03 mol of citric acid)(3 mols baking soda/1 mol of citric acid)
n of baking soda = 0.09 mol of baking soda
mass of baking soda = (0.09 mol of baking soda)(84.00661 g/mol)
mass of baking soda = 7.56 g of baking soda
Answer: 7.56 g
Answer:
SO3 2- which is sulfite
i have to put this because it doesnt let me send the answer like that :)
