Phosphoenol pyruvate enzyme is not part of gluconeogenesis.
<h3>Phosphoenol pyruvate</h3>
The ester formed when pyruvate and phosphate are combined to form an enol results in phosphoenol pyruvate (2-phosphoenolpyruvate, or PEP). As an anion, it exists. In biochemistry, PEP is a crucial intermediary. Involved in glycolysis and gluconeogenesis, it boasts the highest-energy phosphate bond yet discovered in an organism (61.9 kJ/mol). It also plays a role in carbon fixation and the manufacture of a number of aromatic chemicals in plants. In bacteria, it provides energy for the phosphotransferase system. Enolase reacts with 2-phosphoglyceric acid to produce PEP as a result. Pyruvate kinase (PK) converts PEP to pyruvic acid, and this process produces adenosine triphosphate (ATP) via substrate-level phosphorylation. One of the main units of currency for chemical energy in cells is ATP.
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Answer:
I have no idea all I know is poop.
Explanation:
Because I said so
The examination of a microscopic slice of an object with a petrological microscope in order to determine the source of the material, is known as thin-section analysis.
<h3>
What is thin section analysis?</h3>
The microscopic analysis of the content and structure of sediments is known as micromorphology, often known as thin-section analysis. Concepts of plasmic fabric and morphological traits and structures, which date from the early 1960s, were initially established in soil science.
<h3>
What makes petrography significant?</h3>
An essential tool for the fluid inclusion study is petrography. The fundamental purpose of petrography is to classify the fluid phases, such as monophase, biphase, or multiphase, and to deduce the relative chronology of the entrapment of fluid inclusions to determine whether it is primary, secondary, or pseudosecondary.
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Answer:
V₂ = 18.13 L
Explanation:
Given data:
Mole of gas = 1 mol
Initial temperature = 273 K
Initial pressure = 1 atm
Final volume = ?
Final temperature = -41°C (-41+273 = 232 K)
Final pressure = 805 mmHg (805/760 = 1.05 atm)
Solution:
First of all we will calculate the initial volume of gas.
PV = nRT
V = nRT/P
V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm
V = 22.4 L/atm / 1 atm
V = 22.4 L ( initial volume)
Now we will determine the final volume by using equation,
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Now we will put the values.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm × 22.4 L × 232 K / 273 K × 1.05 atm
V₂ = 5196.8 atm .L. K / 286.65 atm.K
V₂ = 18.13 L