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svetlana [45]
3 years ago
9

You have 0.5 L of air at 203 k in an expandable container at constant pressure. You heat the container to 273 k. What is the vol

ume of the air?
A. 0.25 L
B. 1.5 L
C. 0.67 L
0.37 L
Chemistry
1 answer:
Jobisdone [24]3 years ago
4 0
You can use P1V1/T1 = P2V2/T2 but since pressure is constant is becomes V1/T1=V2/T2

V1=0.5 L
T1=203 K
T2=273 K
V2=unknown

0.5L/203 = V2/273
V2= 0.67 L so C

Hope this helps :)
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