Answer:
2.5 moles of KOOH are produced.
Explanation:
1)Given data:
Number of moles of KOOH produced = ?
Number of moles of LiClO = 5 mol
Solution:
Chemical equation:
2LiClO + KHSO₄ → Li₂SO₄ + Cl₂ + KOOH
now we will compare the moles of KOOH and LiClO.
LiClO : KOOH
2 : 1
5 : 1/2×5 = 2.5
2.5 moles of KOOH are produced.
The number of hydrogen atoms that are in 7.80 moles of ammonium sulfide are 3.756 x 10^25 atoms
<u>calculation</u>
Step 1: calculate the moles of H in (NH4)2S
since there are 8 atoms of H in (NH4)2S the moles of
H = 8 x7.80 = 62.4 mole
Step 2: use of Avogadro's law constant to determine the number of H atom
that is 1 mole = 6.02 x10^23 atoms
62.4 moles=? atoms
= [ 62.4 x 6.02 x10^23]/ 1 mole= 3.756 x10^25 atoms
Answer:
appropriately shaped receptors
Explanation:
Answer:
I think Sammy is right because I'm sure the compound contains ionic bonds
NaCl:
Na = + 1
Cl = - 1
hope this helps!
