All categories

3 years ago

What is the difference between pH and pOH?

Chemistry

1 answer:

natali 33 [55]3 years ago

5 0

Answer:

pH measures ratio of H+ ions to OH- ions of substances

pOH measures ratio of OH- ions to H+ ions of substances

Explanation:

pH is a scale which measures the ratio of H+ ions to OH- ions to identify how acidic or basic a substance is. This is because acidic substances have high amounts of H+ ions and low amounts of OH- ions, and therefore have a higher ratio of H+ to OH- ions. (And vice versa for bases, low H+ to OH- ratio) On a pH scale, acidic substances have a pH of 0 to 7, water (neutral pH, not acidic nor basic) has a pH of 7, and bases have a pH of 7-14.

pOH is very similar to pH but measures the opposite: the ratio of OH- ions (indicative of a base) to H+ ions (indicative of an acid). Therefore the pH values are reversed on the scale: Basic substances have pOHs below 7, and acidic substances are above 7 on the pOH scale.

Fundamentally, these two scales measure the same thing is the same way, one just measures the ratio one way (H+:OH-), while the other measured them the other way (OH-:H+), resulting in flipped values on the scales:

pH: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

<---Acidic---> <------Basic------->

pOH: 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

<----Basic----> <-----Acidic------->

Hope this helped!

You might be interested in

PLEASE HELP!

Vadim26 [7]

I know all it's names,but i cann't say the value of yone in english.if u learn it to me i will help u.

8 0

3 years ago

Yall please help me bc there are literally no good answers to this with good votes or with lots of likes tht make sense on brain

NemiM [27]

Answer:

The answer is B i think, sorry if im wrong

Explanation:

3 0

3 years ago

Read 2 more answers

Complete the statements by writing the number

dezoksy [38]

Answer :

The substance is in the gas phase only in region → 5

The substance is in both the liquid and the solid phase in region → 2

The substance is in only the liquid phase in region → 3

The melting point is the temperature at region → 2

The boiling point is the temperature at region → 4

Explanation :

Six phases of substance:

Melting or fusion : In this process the phase changes from solid state to liquid state at constant temperature.

Freezing : In this process the phase changes from liquid state to solid state at constant temperature.

Evaporation : In this process the phase changes from liquid state to gaseous state at constant temperature.

Condensation : In this process the phase changes from gaseous state to liquid state at constant temperature.

Sublimation : In this process the phase changes from solid state to gaseous state without passing through the liquid state at constant temperature.

Deposition : In this process the phase changes from gaseous state to solid state without passing through the liquid state at constant temperature.

3 0

3 years ago

Each

masha68 [24]

13j

14n

7 0

3 years ago

How do you prepare 500 ml of a 1.77M H2SO4 solution from an 18.0 M H2SO4 stock solution?

finlep [7]

Answer:

Molarity Problems Worksheet

M=nV n= # moles

V must be in liters (change if necessary)

1. What is the molarity of a 0.30 liter solution containing 0.50 moles of NaCl?

1.7M

2. Calculate the molarity of 0.289 moles of FeCl3 dissolved in 120 ml of solution?

2.41 M

3. If a 0.075 liter solution contains 0.0877 moles of CuCO4, what is the molarity?

1.2M

4. How many moles of NaCl are present in 600. ml a 1.55 M NaCl solution?

.930 moles

5. How many moles of H2SO4 are present in 1.63 liters of a 0.954 M solution?

1.56 molse

6. How many liters of solution are needed to make a 1.66 M solution containing 2.11 moles of KMnO4?

1.27 g

7. What volume of a 0.25 M solution can be made using 0.55 moles of Ca(OH)2?

2.2 L

For all of the problems below you will need to do a mole-mass conversion. Each problem will involve two steps.

8. What is the molarity in 650. ml of solution containing 63 grams of NaCl?

1.7 M

9. How many grams of Ca(OH)2 are needed to produce 500. ml of 1.66 M Ca(OH)2 solution?

61.5 g

10. What volume of a 0.88 M solution can be made using 130. grams of FeCl2?

1.2 L

Dilution Problems Worksheet

1. How do you prepare a 250.-ml of a 2.35 M HF dilution from a 15.0 M stock solution?

39.2 mL

2. If 455-ml of 6.0 M HNO3 is used to make a 2.5 L dilution, what is the molarity of the dilution?

1.1 M

3. If 65.5 ml of HCl stock solution is used to make 450.-ml of a 0.675 M HCl dilution, what is the molarity of the stock solution?

4.64 M

4. How do you prepare 500.-ml of a 1.77 M H2SO4 dilution from an 18.0 M H2SO4 stock solution?

Take 49.2-ml of 18.0 M H2SO4 stock solution and pour it into a 500-ml volumetric flask. Fill to the 500-ml line with distilled water to make 1.77M H2SO4 solution.

Extra Molarity Problems for Practice

1. How many moles of LiF would be required to produce a 2.5 M solution with a volume of 1.5 L?

3.75 M

2. How many moles of Sr(NO3)2 would be used in the preparation of 2.50 L of a 3.5 M solution?

8.75 M

3. What is the molarity of a 500-ml solution containing 249 g of KI?

3.00 M

4. How many grams of CaCl2 would be required to produce a 3.5 M solution with a volume of 2.0 L?

777 g

Explanation:

I've done this before

6 0

3 years ago