Question

A rocket burns fuel at a rate of 249 kg/s and exhausts the gas at a relative speed of 2 km/s. Find the thrust of the rocket. Answer in units of MN.

Answer 1

0.5MN

Explanation:

Given parameters:

Mass flow rate = 249kg/s

speed of exhaust = 2km/s

Unknown:

Thrust of the rocket = ?

Solution:

Thrust is a force that was captured in the newton's third law which states that "action and reaction are equal and opposite".

Here, the thrust is the force that was exerted by the rocket engine.

  Thrust of the rocket = mass flowrate x speed of exhaust

Now we have to convert km/s to m/s

     1000m = 1km

      2 x $\frac{km}{s}$ x $\frac{1000}{1km}$ = 2000m/s

Thrust = 249 x 2000 = 498,000N

 To MegaNewton, divide by 1000000; this gives 0.5MN

Learn more:

Thrust brainly.com/question/11411375

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