Answer:
W = 1.49 10⁻¹¹ kg
Explanation:
For this problem, let's use Newton's equation of equilibrium
F - W = 0
F = W (1)
Strength can be found from the definition of pressure
P = F / A
F = P A
The radiation pressure for a reflective surface is
P = 2 I / c)
We substitute in equation 1
2 I / c A = W
The intensity is defined by the ratio of the power between the area
I = P / A
P = I A
We substitute
2 P / c = W
W = 2 2.24 10-3 / 3 108
W = 1.49 10⁻¹¹ kg
D thymine
if this is high school than i am tottaly right
Answer:
E. 0.25
Explanation:
Given that
Angular speed ω = 3.5 rad/s
Distance ,r= 0.2 m
Lets take mass of dust bunny = m
We know that
Radial force F = m ω² r
The friction force on the dust bunny Fr
Fr= μ m g
To getting slung off dust bunny from disk
m ω² r = μ m g
ω² r = μ g
3.5² x 0.2 = μ x 10 ( take g =10 m/s²)
μ = 0.245
μ = 0.25
Therefore answer is E
E. 0.25
Answer:
4.03 m/s
Explanation:
Initial momentum = final momentum
(282 kg) (3.50 m/s) + (155 kg) (-1.38 m/s) = (282 kg) (1.10 m/s) + (115 kg) v
v = 4.03 m/s
