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arlik [135]
3 years ago
8

What is a frequency wave

Physics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

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If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed? (1 point)
ludmilkaskok [199]

If electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

<h3>Bahavior of particles in double-slit experiment</h3>

In a double-slit experiment, single particles, such as photons, pass one at a time through a screen containing two slits.

The photons behave like wave and the constructive interfernce of the waves of these photons will generate a high amplitude wave seen as a bright band in the center of the screen.

Thus, if electromagnetic radiation acted like particles in the double-slit experiment, we would observe one bright band would appear in the center of the screen.

Learn more about double slit experiment here: brainly.com/question/4449144

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2 years ago
What would you do if you are caught on thunder storm
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If caught outside in a thunderstorm, find a low spot away from trees, fences, and poles. If your skin tingles and hair stands on end, lightning is about to strike. Crouch down immediately, balancing on the balls of your feet, placing hands on knees with head between them.

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A wave carries _____ from one place to another <br><br> Mechanical waves carry energy through ______
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A wave carries <u>energy</u><u> </u>from one place to another.

mechanical waves carry energy through <u>MEDIUM</u><u>.</u>

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If the pressure of a gas is increased, then the volume will decre
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How large a force is necessary to stretch a 4.0-mm-diameter steel wire from its original length by 1.0%?
jekas [21]

The force needed to stretch the steel wire by 1% is 25,140 N.

The given parameters include;

  • diameter of the steel, d = 4 mm
  • the radius of the wire, r = 2mm = 0.002 m
  • original length of the wire, L₁
  • final length of the wire, L₂ = 1.01 x L₁ (increase of 1% = 101%)
  • extension of the wire e = L₂ - L₁ = 1.01L₁ - L₁ = 0.01L₁
  • the Youngs modulus of steel, E = 200 Gpa

The area of the steel wire is calculated as follows;

A = \pi r^2\\\\ A= 3.142 \times (0.002)^2\\\\ A= 1.257 \times 10^{-5} \ m^2

The force needed to stretch the wire is calculated from Youngs modulus of elasticity given as;

E = \frac{stress}{strain} = \frac{F/A}{e/L} = \frac{FL}{Ae} \\\\F = \frac{EAe}{L}

F = \frac{200 \times 10^9\  \times\  1.257\times 10^{-5}\  \times \ 0.01l_1}{l_1} \\\\F = 25,140\ N

Thus, the force needed to stretch the steel wire by 1% is 25,140 N.

Learn more here: brainly.com/question/21413915

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