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Misha Larkins [42]

3 years ago

6

Under what conditions can an ideal gas undergo a change of state without doing external work?

1 answer:

Cerrena [4.2K]3 years ago

8 0

Nswer

<span>Work done = Pressure * ΔV [ change in volume ] </span>

<span>If ΔV=0, then no work is done </span>

<span>Zero work thermodyanamic process is called ' isochoric process.' </span>

<span>For example if a gas heated in a rigid container: the pressure and temperature </span>
<span>of the gas will increase, but the volume will remain the same. </span>

<span>This is called an isochoric thermodynamic process. </span>

<span>It is actually possible to do work on a system without changing the </span>
<span>volume, as in the case of stirring a liquid</span>

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Two parallel plates that are initially uncharged are separated by 1.7 mm, have only air between them, and each have surface area

yaroslaw [1]

Answer:

$5.63\cdot 10^{-6} C$

Explanation:

The capacitor of a parallel-plate capacitor is given by:

$C=\epsilon_0 \frac{A}{d}$

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d is the separation between the plates

$\epsilon_0$ is the vacuum permittivity

The energy stored in a capacitor instead is given by

$U=\frac{1}{2}\frac{Q^2}{C}$

where

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Substituting the expression we found for C inside the last formula,

$U=\frac{1}{2}\frac{Q^2 d}{\epsilon_0 A}$

And re-arranging it

$Q=\sqrt{\frac{2U\epsilon_0 A}{d}}$

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3 years ago

An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the source voltage is given by ΔV

ra1l [238]

Answer:

t = 5.48 × 10⁻³ s

Explanation:

Given:

ΔV = ΔVmax × sin(2πft)

frequency, f = 16.9Hz

thus,

ΔV = ΔVmax × sin(2π×16.9×ft)

Now,

Let 'R' be the resistance

Also according to the ohms law

i = V/R

where,

i = current

V = voltage

hence,

$i=\frac{\Delta V_{max}sin(2\pi \times 16.9\times t)}{R}$

also, given at time 't' the current in the circuit is 55.0% of the peak current

thus

$i=\frac{55}{100}\times \frac{\Delta V_{max}}{R}=0.55\times \frac{\Delta V_{max}}{R}$

thus,

$0.55\times \frac{\Delta V_{max}}{R}=\frac{\Delta V_{max}sin(2\pi \times 16.9\times t)}{R}$

or

$0.55=sin(2\pi \times 16.9\times t)}$

or

$0.5823=(2\pi \times 16.9\times t)}$

or

t = 5.48 × 10⁻³ s (Answer)

8 0

3 years ago