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Misha Larkins [42]
3 years ago
6

Under what conditions can an ideal gas undergo a change of state without doing external work?

Physics
1 answer:
Cerrena [4.2K]3 years ago
8 0
Nswer 

<span>Work done = Pressure * ΔV [ change in volume ] </span>

<span>If ΔV=0, then no work is done </span>

<span>Zero work thermodyanamic process is called ' isochoric process.' </span>

<span>For example if a gas heated in a rigid container: the pressure and temperature </span>
<span>of the gas will increase, but the volume will remain the same. </span>

<span>This is called an isochoric thermodynamic process. </span>

<span>It is actually possible to do work on a system without changing the </span>
<span>volume, as in the case of stirring a liquid</span>
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Explanation:

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3 years ago
The pressure of a sample of gas is measured as 49 torrent. Convert this to atmosphere ​
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Answer:

P = 0.0644 atm

Explanation:

Given that,

The pressure of a sample of gas is measured as 49 torr.

We need to convert this temperature to atmosphere.

The relation between torr and atmosphere is as follow :

1 atm = 760 torr

1 torr = (1/760) atm

49 torr = (49/760) atm

= 0.0644 atm

Hence, the presssure of the sample of gas is equal to 0.0644 atm.

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2 years ago
The aorta is the main artery from the heart. a typical aorta has an inside diameter of 1.8 cm and carries blood at speeds of up
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Answer:

Explanation:

Volume per unit time flowing   will be conserved

a₁v₁  = a₂ v₂

π r₁² x v₁ = π r₂² x v₂

(0.9 x 10⁻²)² x .35 = ( .45 x 10⁻² )² x v₂

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3 years ago
a reaction occurs in which carbon combines with sulfur to form carbon disulfide is this a chemical reaction or a nuclear reactio
romanna [79]

Answer:

a chemical reaction where electrons mix.

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The weight of spaceman Speff at the surface of planet X, solely due to its gravitational pull, is 389 N. If he moves to a distan
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Answer:

mass of the planet X = 5.6 × 10²³ kg.

Explanation:

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F = GM₁M₂/r²

Where F = gravitational force, M₁ = mass of the speff, M₂ = mass of the planet X, G = gravitational constant r = distance between the speff and the planet X

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M₂ = Fr²/GM₁ .......................... equation 2

Where F = 24.31 N, r = 1.08×18⁴km ⇒( convert to m ) =1.08 × 10⁴  × 1000 m

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Substituting this values in equation 2,

M₂ = 24.13(1.08  × 10⁷ )²/75( 6.67  × 10 ⁻¹¹)

M₂ = 24.13 × 1.17 × 10¹⁴/500.25 × 10⁻¹¹

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M₂ = 0.056 × 10²⁵

M₂ = 5.6 × 10²³ kg.

Therefore mass of the planet X = 5.6 × 10²³ kg.

8 0
3 years ago
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